Answer:
It's either C or D
Explanation:
I'm learning this too! :)
The number of mole present in 87.653 g of lead(II) oxide is 0.393 mole
<h3>Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation:
Mole = mass / molar mass
With the above formula, we can determine the mole of lead(II) oxide. Details below:
<h3>How to determine the mole present in 87.653 g of lead(II) oxide</h3>
- Mass of lead(II) oxide = 87.653 g
- Molar mass of lead(II) oxide = 223.2 g/mol
- Mole of lead(II) oxide =?
Mole = mass / molar mass
Mole of lead(II) oxide = 87.653 / 223.2
Mole of lead(II) oxide = 0.393 mole
Thus, 87.653 g of lead(II) oxide contains 0.393 mole
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Answer:
niobium 1s22s22p63s23p64s23d104p65s24d3
Answer:
i only found the 49, hope it still helps, mate
49. In this question (t½) of C-14 is 5730 years, which means that after 5730 years half of the sample would have decayed and half would be left as it is.
After 5730 years ( first half life) 70 /2 = 35 mg decays and 35 g remains left.
After another 5730 years ( two half lives or 11460 years) 35 /2 = 17.5mg decays and 17.5 g remains left .
After another 5730 years ( three half lives or 17190 years) 17.5 /2 = 8.75mg decays and 8.75g remains left.
after three half lives or 17190 years, 8.75 g of C-14 will be left.
Answer:
have stars that might appear to wobble
often have one star that is brighter than the other
Explanation:
A binary star system is a star system made up of mostly two stars that moves round their common fixed center.
The two orbiting stars are gravitationally bonded to one another and they move round each other.
Most binary stars might appear wobble. One of the stars often appears brighter than the other.