The specific heat of the metal, given the data from the question is 0.60 J/gºC
<h3>Data obtained from the question </h3>
The following data were obtained from the question:
- Mass of metal (M) = 74 g
- Temperature of metal (T) = 94 °C
- Mass of water (Mᵥᵥ) = 120 g
- Temperature of water (Tᵥᵥ) = 26.5 °C
- Equilibrium temperature (Tₑ) = 32 °C
- Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC
- Specific heat capacity of metal (C) =?
<h3>How to determine the specific heat capacity of the metal</h3>
The specific heat capacity of the sample of gold can be obtained as follow:
According to the law of conservation of energy, we have:
Heat loss = Heat gain
MC(T –Tₑ) = MᵥᵥC(Tₑ – Tᵥᵥ)
74 × C(94 – 32) = 120 × 4.184 (32 – 26.5)
C × 4588 = 2761.44
Divide both side by 4588
C = 2761.44 / 4588
C = 0.60 J/gºC
Thus, the specific heat capacity of the metal is 0.60 J/gºC
Learn more about heat transfer:
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The given equilibrium reaction is,

According to Le Chatelier's principle states that when a system in equilibrium is disturbed by varying conditions like concentration, pressure, and temperature of the system, the system tries to counter act the affect by shifting the equilibrium towards the required side.
When
is removed from the system, the concentration of chlorine (
) decreases, the equilibrium is disturbed. So, the system tries to re-establish the equilibrium by moving in that direction which produces more of chlorine, that is towards the reactant side.
The correct answer would be: 1. reaction would go to the left, making more "reactants"
<span>Because protons and neutrons are so much more massive than electrons, almost all of the atomic mass in any atom comes from the nucleus, which contains all of the neutrons and protons.</span>