Answer:
2Al+1.5O2→Al2O3
Thus, 2 mol of Al combine with 1.5 mol of oxygen to form 1 mol of Al2O3.
2 mol of Al corresponds to 2×27=54 g.
Thus, the weight of Al used in the reaction is 54 g.
Answer:
oxygen is limiting reactant
Explanation:
Given data:
Mass of phosphorus = 25.0 g
Mass of oxygen = 50.0 g
What is limiting reactant ?
Solution:
Chemical equation:
P₄ + 5O₂ → P₄O₁₀
Number of moles of P₄:
Number of moles = mass/molar mass
Number of moles = 25.0 g/ 123.89 g/mol
Number of moles = 0.20 mol
Number of moles of O₂:
Number of moles = mass/molar mass
Number of moles = 50.0 g/ 32 g/mol
Number of moles = 1.56 mol
now we will compare the moles of reactants with product:
P₄ : P₄O₁₀
1 : 1
0.20 : 0.20
O₂ : P₄O₁₀
5 : 1
1.56 : 1/5×1.56 = 0.312 mol
Less number of moles of product are formed by the oxygen thus it will act as limiting reactant.
The power for the first tank is 2kW and the second tank is 150 kw for the theoretical pumping power lifts a solution with a density of 1200 kg/m³ from a tank to a reservoir.
<h3>What is power?</h3>
Power is the amount of energy in kilowatt which is required to do some work that needs energy known as power it is the multiplication of pressure and the flow of liquid.
Power for the tank = pressure of water × flow of water
Substituting the value,
power = 1 × 2 = 2 kW = P1
power = 10 × 15 = 150 kW = P2
Therefore, a solution with a density of 1200 kg/m³ from a tank to a reservoir power for the first tank is 2kW and for the second tank is 150 kW for the theoretical pumping power lifts.
Learn more about power, here:
brainly.com/question/24091709
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You need to use Avogadro's constant to convert from atoms of carbon to moles of carbon.
1.71*10^24 atoms C * (1 mole/6.022*10^23 atoms) = 2.84 moles of carbon
