Question

The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 5 minutes. Find the probability that a randomly selected passenger has a waiting time less than 1.75 minutes.

Answer 1

Answer:

0.35

Step-by-step explanation:

we know that

The formula to use for uniform distribution is equal to

$P( X < x) = \frac{x-a}{b-a}$

where,

b is the upper limit of the distribution which is 5 minutes in this case.

a is the lower limit of the distribution which is 0 minutes in this case.

x is the concerned value which is 1.75 minutes in this case.

substitute the given values

$P( X< 1.75) = \frac{1.75-0}{5-0}=0.35$

That means

The probability that a randomly selected passenger has a waiting time less than 1.75 minutes is 0.35