I really need help. I've been stuck on this question for almost an hour.
1 answer:
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Given that ∠B ≅ ∠C.
to prove that the sides AB = AC
This can be done by the method of contradiction.
If possible let AB =AC
Then either AB>AC or AB<AC
Case i: If AB>AC, then by triangle axiom, Angle C > angle B.
But since angle C = angle B, we get AB cannot be greater than AC
Case ii: If AB<AC, then by triangle axiom, Angle C < angle B.
But since angle C = angle B, we get AB cannot be less than AC
Conclusion:
Since AB cannot be greater than AC nor less than AC, we have only one possibility. that is AB =AC
Hence if angle B = angle C it follows that
AB = AC, and AB ≅ AC.
Here is your answer
B) 1/125
REASON:
Given,
for F (3)
Putting x=3, in above function we get
HOPE IT IS USEFUL
B) 1/125
REASON:
Given,
for F (3)
Putting x=3, in above function we get
HOPE IT IS USEFUL