The given question is incomplete. The complete question is as follows.
The enthalpy of formation of ozone is 142.7 kJ / mol. The bond energy of is 498 kJ / mol. What is the average O=O bond energy of the bent ozone molecule O=O=O?
Explanation:
The given reaction is as follows.
The value of for 2 moles of ozone is = 285.4 kJ/mol.
So, in this reaction three O=O bonds are broken down and four O-O bonds of ozone are formed.
Expression for the enthalpy of reaction is as follows.
285.4 kJ/mol =
285.4 kJ/mol =
-1208.6 kJ/mol =
= 604.3 kJ/mol
Now, the average bond enthalpy of O-O bond in is as follows.
= kJ/mol
= 201.43 kJ/mol
Thus, we can conclude that for the given reaction average bond enthalpy of an oxygen-oxygen bond in is 201.43 kJ/mol.