Answer:
0.3 mol
Explanation:
Assuming HCl is in excess and Zn is the limiting reagent,
from the balanced equation, we can see the mole ratio of Zn:H2 = 1:1,
which means, each mole of zinc reacted gives 1 mole of H2.
So, if 0.30 mol Zn is added, the no. of moles of H2 produced will also be 0.3 mol, since the ratio is 1:1.
Question: Given the balanced equation representing a reaction:
2H2 + O2 ==>2H2O
What is the total mass of water formed when 8 grams of hydrogen reacts completely with 64 grams of oxygen?
(1) 18 g (3) 56 g
(2) 36 g (4) 72 g
Answer:
"72 gram" is the total mass of water formed when 8 grams of hydrogen reacts completely with 64 grams of oxygen
Explanation:
We will do stoichiometry in this kind of problem:
Therefore, the total mass of water formed is 72 g.
Answer:
Concentration of Na₂SO₃ is 0.0533M
Explanation:
To obtain concentration of Na₂SO₃ it is necessary to obtain moles of primary standard, KIO₃ in the standarization:
0.4991g × (1mol / 214g) = 2.332x10⁻³ mol KIO₃ / 0.2500L = 9.329x10⁻³M
As you take 50.00mL of this solution, moles are:
0.05000L × (9.329x10⁻³mol / L) = <em>4.664x10⁻⁴ moles KIO₃</em>
Now, the reaction of Na₂SO₃ with KIO₃ is:
KIO₃(aq) + 3 Na₂SO₃(aq) → KI(aq) + 3 Na₂SO₄(aq)
That means 1 mole of KIO₃ reacts with 3 moles of Na₂SO₃. Thus, moles of Na₂SO₃ that reacts are:
4.664x10⁻⁴ moles KIO₃ × (3 mol Na₂SO₃ / 1 mol KIO₃) = <em>1.399x10⁻³ mol Na₂SO₃</em>
As 26.25mL of titrant were consumed, concentration of Na₂SO₃ is:
1.399x10⁻³ mol Na₂SO₃ / 0.02625L = <em>0.0533M</em>
Answer:
Explanation:
According to the Dalton's law of partial pressure, the total pressure of the gaseous mixture is equal to the sum of the pressure of the individual gases.
Partial pressure of carbon dioxide = 401 mmHg
Partial pressure of hydrogen gas = 224 mmHg
Total pressure,P = sum of the partial pressure of the gases = 401 + 224 mmHg = 625 mmHg
Also, the partial pressure of the gas is equal to the product of the mole fraction and total pressure.
So,
Similarly,