Please help me on this

Find the rate of change from the given table.

Ymorist [56]

The rate of change would be D. 4

4 0

2 years ago

Just ignore number 7 it’s 8 I need help on, it tried to attempt it myself but it wasn’t working for me

ArbitrLikvidat [17]

1 hm=100m

1.5hm=150 meters each tower is from each other.

500km(1000m/1km)=500,000 meters the wire covers.

500,000/150 = 3333.33 towers. Just because we want to be safe and have enough towers we can say we have 3334 towers in the span of 500,000 meters.

B)

1kV=1000V

500kV(1000V/1kV)= 500,000 V

There are 1.2 volts in a AA battery so we divide 500,000/1.2 = 416666.67 times larger

3 0

3 years ago

Find out the number of combinations and the number of permutations for 8 objects taken 6 at a time. Express your answer in exact

umka2103 [35]

Solution:

The permutation formula is expressed as

$\begin{gathered} P^n_r=\frac{n!}{(n-r)!} \\ \end{gathered}$

The combination formula is expressed as

$\begin{gathered} C^n_r=\frac{n!}{(n-r)!r!} \\ \\ \end{gathered}$

where

$\begin{gathered} n\Rightarrow total\text{ number of objects} \\ r\Rightarrow number\text{ of object selected} \end{gathered}$

Given that 6 objects are taken at a time from 8, this implies that

$\begin{gathered} n=8 \\ r=6 \end{gathered}$

Thus,

Number of permuations:

$\begin{gathered} P^8_6=\frac{8!}{(8-6)!} \\ =\frac{8!}{2!}=\frac{8\times7\times6\times5\times4\times3\times2!}{2!} \\ 2!\text{ cancel out, thus we have} \\ \begin{equation*} 8\times7\times6\times5\times4\times3 \end{equation*} \\ \Rightarrow P_6^8=20160 \end{gathered}$

Number of combinations:

$\begin{gathered} C^8_6=\frac{8!}{(8-6)!6!} \\ =\frac{8!}{2!\times6!}=\frac{8\times7\times6!}{6!\times2\times1} \\ 6!\text{ cancel out, thus we have} \\ \frac{8\times7}{2} \\ \Rightarrow C_6^8=28 \end{gathered}$

Hence, there are 28 combinations and 20160 permutations.

7 0

1 year ago

What is the value of the following expression 1.8 + 0.5(y + 6) - 2 t the power of 3 when y = 14?

aalyn [17]

Answer: The answer should be 38.

I also saw that you placed a t after the -2 so I wasn't sure if it was a mistake or if it was on purpose or you left another t out of the problem on accident.

Step-by-step explanation:

2.3 (14+6) -2 to the power of three

2.3 (20) -2 to the power of three

2.3 (20) -8

46-8

38

I really hoped this helped and if I got it wrong with the t just reply to me c:

4 0

3 years ago

A grading scale is set up for 1000 students' test scores. It assumes the

astra-53 [7]

Answer:

464 students will score between 48 and 75. Using the z-distribution, we measure how many standard deviations each score is from the mean, then find the p-value associated with each score to find the proportion, and from the proportion, we find how many out of 1000.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

It assumes the scores are normally distributed with a mean score of 75 and a standard deviation of 15.

This means that $\mu = 75, \sigma = 15$

How many students will score between 48 and 75?

First we find the proportion, which is the pvalue of Z when X = 75 subtracted by the pvalue of Z when X = 48. So

X = 75

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{75 - 75}{15}$

$Z = 0$

$Z = 0$ has a p-value of 0.5

X = 48

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{48 - 75}{15}$

$Z = -1.8$

$Z = -1.8$ has a p-value of 0.0359

1 - 0.0359 = 0.4641

Out of 1000:

0.4641*1000 = 464

464 students will score between 48 and 75. Using the z-distribution, we measure how many standard deviations each score is from the mean, then find the p-value associated with each score to find the proportion, and from the proportion, we find how many out of 1000.

7 0

3 years ago