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sineoko [7]
3 years ago
11

Type A.

Physics
1 answer:
pantera1 [17]3 years ago
5 0

Answer:

a) 750W

b) 800W

  1018.9W

c) the circular frame

Explanation:

a) To find the electric flux you use the following formula:

\Phi_E=EAcos\theta=EA

where you have assumed that the plane of the loop and B are perpendicular between them.

By replacing you obtain:

\Phi_E=(2*10^4N/C)(0.25m)(0.15m)=750W

b) In order to calculate the electric flux in a square frame you first calculate the perimeter of the rectangular frame of wire:

P = 0.25m+0.25m+0.15m+0.15m=0.8m

A square with this length will have sides of 0.2m

Hence. you have that the electric flux is:

\Phi_E=(2*10^4N/C)(0.2m)^2=800W

for a circular frame you have that the radius is:

s=2\pi r\\\\r=\frac{s}{2\pi}=\frac{0.8m}{2\pi}=0.127m

Then, the electric flux will be:

\Phi_E=(2*10^4N/C)(\pi)(0.127m)^2=1018.9W

c) The electric flux is maximum in the circular frame.

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A horizontal force of 750 N is needed to overcome the force of static friction between a level floor and a 250-kg crate. If g-9.
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