Question

Type A.

Answer 1

Answer:

a) 750W

b) 800W

  1018.9W

c) the circular frame

Explanation:

a) To find the electric flux you use the following formula:

$\Phi_E=EAcos\theta=EA$

where you have assumed that the plane of the loop and B are perpendicular between them.

By replacing you obtain:

$\Phi_E=(2*10^4N/C)(0.25m)(0.15m)=750W$

b) In order to calculate the electric flux in a square frame you first calculate the perimeter of the rectangular frame of wire:

P = 0.25m+0.25m+0.15m+0.15m=0.8m

A square with this length will have sides of 0.2m

Hence. you have that the electric flux is:

$\Phi_E=(2*10^4N/C)(0.2m)^2=800W$

for a circular frame you have that the radius is:

$s=2\pi r\\\\r=\frac{s}{2\pi}=\frac{0.8m}{2\pi}=0.127m$

Then, the electric flux will be:

$\Phi_E=(2*10^4N/C)(\pi)(0.127m)^2=1018.9W$

c) The electric flux is maximum in the circular frame.