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4 years ago

Match up the following set of words with their definitions:

Physics

1 answer:

jolli1 [7]4 years ago

5 0

Mass is number 2. Vector is 5. Force is 3. Weight is 1. Net force is 6. magnitude is 4.

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What supports a white dwarf against the crush of gravity?

weqwewe [10]

Answer: In particular, electron degeneracy pressure is what supports white dwarfs against gravitational collapse, and the Chandrasekhar limit (the maximum mass a white dwarf can attain) arises naturally due to the physics of electron degeneracy.

Explanation:

5 0

3 years ago

Two identical conducting small spheres are placed with their centers 0.290 m apart. One is given a charge of 12.0 nC and the oth

Solnce55 [7]

Answer:

Force between two identical conducting ball will be $2.65\times 10^{-5}N$

Explanation:

We have given there is two identical conducting small spheres having charge $q_1=12nC=12\times 10^{-9}C$ and $q_2=-21nC=-21\times 10^{-9}C$

Distance between centers of the ball is 0.290 m

So r = 0.290 m

We have to fond the electric force between the balls

According to Coulomb's law force between two charges is given by

$F=\frac{1}{4\pi \epsilon _0}\frac{q_1_2}{r^2}=\frac{Kq_1q_2}{r^2}$

So force $F=\frac{9\times 10^{9}\times 12\times 10^{-9}\times 21\times 10^{-9}}{0.293^2}=2.65\times 10^{-5}N$

So force between two identical conducting ball will be $2.65\times 10^{-5}N$

4 0

3 years ago

The wall of a large room is covered with acoustic tile in which small holes are drilled 4.6 mm from center to center. How far ca

Zielflug [23.3K]

Answer:

L= 27.42m

Explanation:

We have the variables

$D=4.6*10^{-3}m$

$d= 4*10^{-3}m$

$\lambda = 550*10^{-9}m$

Use the relation,

$L=\frac{D}{\theta_R} = \frac{D_d}{1.22\lambda}$

$L= \frac{(4.6*10^{-3}m)(4*10^{-3}m)}{1.22(550*10^{-9}m)}$

$L= 27.42m$

8 0

4 years ago

Two resistors connected in series have an equivalent resistance of 724.5 Ω, when they are connected in parallel, their equivalen

dybincka [34]

Answer:

544.65 ohm and 179.84 ohm

Explanation:

Hello

Let

Resistor 1 (R1) and Resistor 2 (R2)

in series $R_{eq} =R1+R2$

in parallel

$\frac{1}{R_{eqp} } =\frac{1}{R1} +\frac{1}{R2}\\\\R1=R_{eqs} -R2\\\\R1 =724.5-R2 (equation 1)\\ R_{eqp}}=\frac{R1*R2}{R1+R2}\\\\\ 135.2 = \frac{R1*R2}{R1+R2}(equation 2)\\\\\\\\replacing 1 in \ 2\\\\probema data$

$135.2=\frac{(724.5-R2)(R2)}{724.5-R2+R2} }\\135.2=\frac{(-R_{2} ^{2}+724.5R2) }{724.5}\\ 135.2*724.5=-R_{2} ^{2}+724.5R_{2}\\\\R_{2} ^{2} -724.5R_{2} +97952.4 =0\\R_{2} =\frac{724.5 \±\sqrt{(-724.5^{2})-4(1)(97952.4) } }{2(1)}\\R_{2} =\frac{724.5\±\sqrt{(133092.25) } }{2(1)}\\\\R_{2} =\frac{724.5+364.81810}{2} \\R_{2} =544.65 ohm\\\\R_{2} =\frac{724.5-364.81810}{2} =179.84 ohm$ \\\\

let R2=544.65 and replace in equation 1

R1=724.5-544.65

R1=179.85

so, the resistors are 544.65 ohm and 179.84 ohm

Have a great day

7 0

4 years ago

9. Luke is an astronaut that moves his position in the space shuttle by climbing a

BartSMP [9]

Explanation:

Remember that power is defined as how much Work is done per unit of time.

$P = \frac{dW}{dt}$

Work is defined as the amount of force applied across a certain distance.

$W = F*d$

Since in both cases of climbing the ladder (on Earth and the moon), Luke coveres the same amount of <em>distance </em>in the same amount of <em>time</em>, we are only left with one difference between the two cases - gravity.

If you were to carry your backpack on the moon with the same load of text books, it would take less force to pick it up on the moon. Therefore, Luke expends less effort on the environment with less gravity - the moon.

To find the difference factor - you would want to divid the gravitational contants between earth and the moon.

6 0

3 years ago

Read 2 more answers