Answer:
r₁/r₂ = 1/2 = 0.5
Explanation:
The resistance of a wire is given by the following formula:
R = ρL/A
where,
R = Resistance of wire
ρ = resistivity of the material of wire
L = Length of wire
A = Cross-sectional area of wire = πr²
r = radius of wire
Therefore,
R = ρL/πr²
<u>FOR WIRE A</u>:
R₁ = ρ₁L₁/πr₁² -------- equation 1
<u>FOR WIRE B</u>:
R₂ = ρ₂L₂/πr₂² -------- equation 2
It is given that resistance of wire A is four times greater than the resistance of wire B.
R₁ = 4 R₂
using values from equation 1 and equation 2:
ρ₁L₁/πr₁² = 4ρ₂L₂/πr₂²
since, the material and length of both wires are same.
ρ₁ = ρ₂ = ρ
L₁ = L₂ = L
Therefore,
ρL/πr₁² = 4ρL/πr₂²
1/r₁² = 4/r₂²
r₁²/r₂² = 1/4
taking square root on both sides:
<u>r₁/r₂ = 1/2 = 0.5</u>
Answer:
24.57 revolutions
Explanation:
(a) If they do not slip on the pavement, then the angular acceleration is
(b) We can use the following equation of motion to find out the angle traveled by the wheel before coming to rest:
where v = 0 m/s is the final angular velocity of the wheel when it stops, = 95rad/s is the initial angular velocity of the wheel, is the deceleration of the wheel, and is the angle swept in rad, which we care looking for:
As each revolution equals to 2π, the total revolution it makes before stop is
154.375 / 2π = 24.57 revolutions
Complete Question
A gas gun uses high pressure gas tp accelerate projectile through the gun barrel.
If the acceleration of the projective is : a = c/s m/s2
Where c is a constant that depends on the initial gas pressure behind the projectile. The initial position of the projectile is s= 1.5m and the projectile is initially at rest. The projectile accelerates until it reaches the end of the barrel at s=3m. What is the value of the constant c such that the projectile leaves the barrel with velocity of 200m/s?
Answer:
The value of the constant is
Explanation:
From the question we are told that
The acceleration is
The initial position of the projectile is s= 1.5m
The final position of the projectile is
The velocity is
Generally
and acceleration is
so
=>
integrating both sides
Now for the limit
a = 200 m/s
b = 0 m/s
c = s= 3 m
d == 1.5 m
So we have
=>
The energy stored by a system of capacitors is given by
where Ceq is the equivalent capacitance of the system, and V is the voltage applied.
In the formula, we can see there is a direct proportionality between U and C. This means that if we want to increase the energy stored by 4 times, we have to increase C by 4 times, if we keep the same voltage.
Calling
the capacitance of the original capacitor, we can solve the problem by asking that, adding a new capacitor with
, the new equivalent capacitance of the system
must be equal to
. If we add the new capacitance X in parallel, the equivalent capacitance of the new system is the sum of the two capacitance
and since Ceq must be equal to 4 C1, we can write
from which we find
Answer:
b) se duplica
Explanation:
The disk is moving with constant angular velocity, let's call it .
The linear velocity of a point on the disk is given by
where r is the distance of the point from the axis of rotation.
In this problem, the object is moved at a distance twice as far as the initial point, so
Therefore, the new linear velocity is
So, the velocity has doubled, and the correct answer is
b) se duplica