प्रकाशको आवर्तनको परिभाषा लेख्नुहोस् । कन्भेक्स ऐनाको अगाडि तपाई उभियौ भने तपाईको कस्तो आकृति बन्छ, लेख्नर

You are working with a team to design a better electron microscope. To precisely control the beam of electrons, your team decide

rewona [7]

Answer and Explanation:

(a) The attached image below shows the diagram of a CRT in the helmholtz coils and well labelled with details

(b). The electron will follow a circular path which travels along under constant magnetic field

$r = \frac{mV}{qB}$

where m = mass of electron, V = velocity of electron, q = charge of the electron and B = magnetic field strength

4 0

2 years ago

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A satellite is in a circular orbit around an unknown planet. The satellite has a speed of 1.75 104 m/s, and the radius of the or

Arisa [49]

Answer:

v = 1.32 10² m

Explanation:

In this case we are going to use the universal gravitation equation and Newton's second law

F = G m M / r²

F = m a

In this case the acceleration is centripetal

a = v² / r

The force is given by the gravitational force

G m M / r² = m v² / r

G M/r = v²

Let's calculate the mass of the planet

M = v² r / G

M = (1.75 10⁴)² 5.00 10⁶ / 6.67 10⁻¹¹

M = 2.30 10²¹ kg

With this die we clear the equation to find the orbit of the second satellite

v = √ G M / r

v = √ (6.67 10⁻¹¹ 2.30 10²¹ / 8.75 10⁶)

v = 1.32 10² m

8 0

2 years ago

Pls help Asapppppppppp.It is due in a little bit.

bija089 [108]

C I’m pretty sure !

7 0

2 years ago

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The membrane that surrounds a certain type of living cell has a surface area of 4.3 x 10-9 m2 and a thickness of 1.1 x 10-8 m. A

Nadusha1986 [10]

Answer:

The charge resides on the outer surface = $1.245 \times 10^{-12}$ C

Explanation:

Surface area of cell $(A) = 4.3\times 10^{-9} m^{2}$

Separation between two plate $(d) = 1.1 \times 10^{-8} m$

Dielectric constant $(k) = 4.2$

Potential difference $(\Delta V) = 85.7 \times 10^{-3} V$

The capacitance of parallel plate capacitor in free space is given by,

$C = \frac{\epsilon_{o} A }{d}$

Where $\epsilon_{o} =$ permittivity of free space = $8.85 \times 10^{-12}$

The Capacitance of capacitor is increase by $k$ times when it placed in dielectric medium.

$C_{dielectric} = \frac{k \epsilon_{o} A }{d}$

And we know that, $C = \frac{Q}{ \Delta V}$

So charge on the outer surface is given by,

$Q = \frac{k \epsilon A \Delta V }{d}$

$Q = \frac{4.2 \times 4.3 \times 10^{-9} \times 8.85 \times 10^{-12} \times 85.7\times 10^{-3} }{1.1 \times 10^{-8} }$

$Q = 1.245 \times 10^{-12}$

3 0

3 years ago

A meteoroid is moving towards a planet. It has mass m = 0.78×109 kg and speed v1 = 4.1×107 m/s at distance R1 = 2.8×107 m from t

wariber [46]

Answer:

$PE=81.755\, J$

Explanation:

Given that:

mass of meteoroid, $m=7.8\times 10^8 \,kg$

radial distance from the center of the planet, $R= 2.8\times 10^7 m$

mass of the planet, $M=4.4\times 10^{25}\, kg$

<u>For gravitational potential energy we have:</u>

$PE=G\frac{M.m}{R}$

substituting the respective values:

$PE=6.67\times 10^{-11}\times \frac{4.4\times 10^{25}\times 7.8\times 10^8}{2.8\times 10^7}$

$PE=81.755\, J$

5 0

2 years ago