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Arisa [49]
2 years ago
9

प्रकाशको आवर्तनको परिभाषा लेख्नुहोस् । कन्भेक्स ऐनाको अगाडि तपाई उभियौ भने तपाईको कस्तो आकृति बन्छ, लेख्नर

Physics
1 answer:
allochka39001 [22]2 years ago
4 0
A diagram alright of the
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A ball of mass m falls vertically, hits the floor with a speed ui , and rebounds with a speed u f . what is the magnitude of the
Sholpan [36]

Answer:

Change of momentum = M (Vf - (-Vi))   where V represents the scalar speeds of the ball or

I = M (ui + uf)  and I is the impulse ΔM V = I     Force = Change in Momentum

5 0
2 years ago
What are the coordinates of the point that is 1/5 of the way from A(-7,-4) to B(3, 6)?
Olegator [25]

Answer:

coordinate will be

r = (1.33,4.33)

Explanation:

As we know that if a point will divide two given coordinates in m : n ratio

then in that case the point is given as

x = \frac{mx_1 + nx_2}{m+n}

y = \frac{my_1 + ny_2}{m+n}

here we know that two points are

(-7, -4) and (3, 6)

and the ratio is given as 1 : 5

now from above formula we will have

x = \frac{1(-7) + 5(3)}{1 + 5} = 1.33

y = \frac{1(-4) + 5(6)}{1 + 5} = 4.33

so coordinate will be

r = (1.33, 4.33)

7 0
3 years ago
If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C?
Natalka [10]
By using the combined gas law which says that P1V1/T1 = P2V2/T2, assuming constant pressure, the volume at the required temperature can be obtained.((0.002 m3)(50+273.15))/(20+273.15) = volume 2 at 50 degrees C.
This gives the answer 0.0022048 m3
5 0
3 years ago
Read 2 more answers
An older camera has a lens with a focal length of 60mm and uses 34-mm-wide film to record its images. Using this camera, a photo
lesya692 [45]

Answer:

24.71 mm

Explanation:

Distance is proportional to focal length, so

d∝f

which means

\frac{d'_1}{d'_2}=\frac{f_1}{f_2}

Magnification of first lens

M_2=-\frac{d'_1}{d_1}

                   and

M_2=\frac{h'_1}{h_1}

Similarly, magnification of second lens

M_2=-\frac{d'_2}{d_1}

                   and

M_2=\frac{h'_2}{h_1}

From the above equations we get

\frac{M_1}{M_2}=\frac{d'_1}{d_2'}

                   and

\frac{M_1}{M_2}=\frac{h'_1}{h_2'}

which means,

\frac{d'_1}{d_2'}=\frac{h'_1}{h_2'}

and

\frac{d'_1}{d_2'}=\frac{f_1}{f_2}

So, we get

\frac{f_1}{f_2}=\frac{h'_1}{h_2'}\\\Rightarrow f_2=f_1\times\frac{h_2'}{h'_1}\\\Rightarrow f_2=60\times\frac{14}{34}=24.71\ mm

∴ Focal length should this camera's lens is 24.71 mm

6 0
3 years ago
How many times did thomas edison fail before inventing the lightbulb
Rom4ik [11]

Answer:

he failed thousands of times

Explanation:

There is no known number for his failings. Edison may have failed in many of his experiments and in his schooling, but he had something better working in his favor. He had great determination and persistence.

He failed thousands of times in an attempt to develop an electric light, the great Edison simply viewed each unsuccessful experiment as the elimination of a solution that wouldn’t work, thereby moving him that much closer to a successful solution.

4 0
2 years ago
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