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tankabanditka [31]
3 years ago
10

There are 40% more black balls than white balls in a bag.

Mathematics
1 answer:
Paladinen [302]3 years ago
4 0
There is no answer to this question.

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A jar contains 3 red, 2 white, and 1 green marble. Aside from color, the marbles are indistinguishable. Two marbles are drawn at
IRISSAK [1]

Answer:

0.6

Step-by-step explanation:

A permutation is an arrangement of outcomes whereas a combination is a grouping of outcomes.

Order matters in case of permutations but does not matter in combinations.

Given:

Number of red marbles = 3

Number of white marbles = 2

Number of green marbles = 1

To find: probability of picking 4 marbles and getting one of each color

Solution:

Total number of outcomes = 6_C__4 = \frac{6!}{4!\,2!}=\frac{6\times 5\times 4!}{4!\times 2}=15

Number of favourable outcomes = 2 red, 1 white and 1 green marble + 1 red, 2 white and 1 green marble = 3_C_2\,2_C_1\,1_C_1+3_C_1\,2_C_2\,1_C_1 = \frac{3!}{2!\,1!}\times \frac{2!}{1!\,1!}\times 1+\frac{3!}{2!\,1!}\times 1\times 1=6+3=9

So, probability of picking 4 marbles and getting one of each color = Number of favourable outcomes/Total number of outcomes =\frac{9}{15}=\frac{3}{5}=0.6

4 0
3 years ago
(x2yz3)2 how do you solve
AVprozaik [17]
<u>Use the distributive property to solve. Multiply the two by every term in the parentheses and then combine alike terms.</u>
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4 years ago
Is the LCM ( least common multiple) of two numbers ( always,sometimes,never) the product of the two numbers?
Scorpion4ik [409]
In arithmetic and number theory, the least common multiple, lowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(a, b), is the smallest positive integer that is divisible by both a and b. SOOO, no there can be a lower number then both multiplied by each other.
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A scientist is experimenting with bacteria in his laboratory He starts out with 3 bacteria
never [62]
X+1 to the second power
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3 years ago
What is the answer to - 1/3 (x+6)=0
Sauron [17]
(-\frac{1}{3})(x+6)=0\\\\\frac{1}{3}(x+6)*3=0*3\\\\-1(x+6)=0\\\\-(x+6)*-1=0*-1\\\\x+6=0\\\\x=-6
3 0
3 years ago
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