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3 years ago

PLEASE ANSWER!!!!! I WILL MARK YOU AS BRAINLIEST!!!!! IT IS HIGHLY APPRECIATED!!! :)

Mathematics

1 answer:

kkurt [141]3 years ago

3 0

Answer:

A number less than 4 was rolled 18 times.

The number cube was rolled 50 times. The relative frequency of rolling a number less than 4 is 36%.

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Solve the system by graphing.

igor_vitrenko [27]

Answer:

Hi There the correct answer is {x,y} = {-1,-10}

System of Linear Equations entered :

[1] 3x - y = 7

[2] 4x - 2y = 16

Graphic Representation of the Equations :

y + 3x = 7 -2y + 4x = 16

Solve by Substitution :

// Solve equation [1] for the variable y

[1] y = 3x - 7

// Plug this in for variable y in equation [2]

[2] 4x - 2•(3x-7) = 16

[2] -2x = 2

// Solve equation [2] for the variable x

[2] 2x = - 2

[2] x = - 1

// By now we know this much :

x = -1

y = 3x-7

// Use the x value to solve for y

y = 3(-1)-7 = -10

Solution :

{x,y} = {-1,-10}

Hope it helps!

8 0

3 years ago

G ^-1(3)= A.-1 B.0 C.3 D. 5 Please help me understand this!!

Natasha2012 [34]

The answer the 3,

First you have to apply the exponent rule which is 1 - 3• 1/g

Then you multiply the fractions - 1•3/g

Then multiply the numbers 1 and 3, which is 3, so there you have it 3/g, or 3, they’re the same thing.

8 0

3 years ago

Q6: 24 students in a class took an algebra test.

german

Answer:

25%

Step-by-step explanation:

18/24 passed that reduces 3/4.

So 1/4 didn't pass

4 0

3 years ago

PLEASE HELP! WILL GIVE BRAINLIEST

kiruha [24]

Answer:

Step-by-step explanation:

Angle JID is supplementary to Angle JIH so:

180- Angle JIH= Angle JID

180-107=73

Angle JID is opposite to Angle AJF(angle x)

Opposite angles are always equal

Angle JID=Angle AJF(x)

73=Angle AJF(x)

8 0

3 years ago

Read 2 more answers

The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.

Stells [14]

Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.

Given that the second sphere has twice the radius of the given sphere.

Radius of the second sphere = 2 × 2.5 = 5 inches

Thus, the radius of the second sphere is 5 inches.

Part b: we need to determine the volume of the second sphere.

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=5$ , we get,

$V=\frac{4}{3} (3.14)(125)$

$V=\frac{1580}{3}$

$V=523.3333 \ in^3$

Rounding off to two decimal places, we have,

$V=523.33 \ in^3$

Thus, the volume of the second sphere is 523.33 in³

Part c: We need to determine the radius of the third sphere

Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.

Hence, we have,

Diameter of the third sphere = $\frac{3}{4} (5)=3.75$

Radius of the third sphere = $\frac{3.75}{2} =1.875$

Thus, the radius of the third sphere is 1.875 inches

Part d: We need to determine the volume of the third sphere

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=1.875$ , we get,

$V=\frac{4}{3} (3.14)(1.875)^3$

$V=\frac{4}{3} (3.14)(6.59)$

$V=27.5901 \ in^3$

Rounding off to two decimal places, we have,

$V=27.59 \ in^3$

Thus, the volume of the third sphere is 27.59 in³

4 0

4 years ago