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m_a_m_a [10]
3 years ago
15

Simplify. Can you explain it also?

Mathematics
1 answer:
Doss [256]3 years ago
8 0

Answer:

The answer is

<h2>\frac{3c}{4e}</h2>

Step-by-step explanation:

<h3>\frac{9 {c}^{3}d {e}^{2}  }{12 {c}^{2} d {e}^{3} }</h3>

To solve the fraction reduce the fraction with d

That's we have

<h2>\frac{9 {c}^{3}  {e}^{2} }{12 {c}^{2} {e}^{3}  }</h2>

Next simplify the expression using the rules of indices to simplify the letters in the fraction

<u>For c </u>

Since they are dividing we subtract the exponents

We have

<h2>{c}^{3}  \div  {c}^{2}  =  {c}^{3 - 2}  = c^{1}  = c</h2>

<u>For </u><u>e</u>

<h2>e^{2}  \div  {e}^{3}  = e^{2 - 3}  =  {e}^{ - 1}  =  \frac{1}{e}</h2>

Substituting them into the expression we have

<h2>\frac{9c}{12e}</h2>

Reduce the fraction by 3

We have the final answer as

<h2>\frac{3c}{4e}</h2>

Hope this helps you

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tangare [24]

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Step-by-step explanation:

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2 years ago
From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.
zzz [600]

Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}

, where \overline{x} = sample mean.

z*= critical z-value

n= sample size.

\sigma = Population standard deviation.

By considering the given question , we have

\overline{x}= 21.69

\sigma=3.23

n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}

=21.69\pm (1.96)\dfrac{1.7}{7.61577}

=21.69\pm (1.96)(0.223221)

\approx21.69\pm0.83

=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

7 0
3 years ago
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