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kotegsom [21]
3 years ago
7

Find the average value of f(x)=2/x over the interval [1, 3].

Mathematics
1 answer:
Zanzabum3 years ago
3 0

\bf slope = m = \cfrac{rise}{run} \implies  \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby  \begin{array}{llll} average~rate\\ of~change \end{array}\\\\ -------------------------------\\\\ f(x)= \cfrac{2}{x}  \qquad  \begin{cases} x_1=1\\ x_2=3 \end{cases}\implies \cfrac{f(3)-f(1)}{3-1}\implies \cfrac{\quad \frac{2}{3}-\frac{2}{1}\quad }{2} \\\\\\ \cfrac{\quad \frac{2-6}{3}\quad }{2}\implies \cfrac{\quad \frac{-4}{3}\quad }{\frac{2}{1}}\implies \cfrac{-4}{3}\cdot \cfrac{1}{2}\implies -\cfrac{2}{3}

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Yo! Solving linear equations with integers! These are just some practice exercises I need help with! So they should probably be
drek231 [11]

Answer:

Step-by-step explanation:

<h3>Solving linear equation with one variable:</h3>

   1) -4 + 3x = 4x - 8

        Add 4 to both sides

      -4 + 3x + 4 = 4x - 8 +  4

               3x     = 4x - 4

Subtract 4x from both sides,

        3x - 4x = -4x + 4x - 4

              -x   = -4

                \sf \boxed{\bf x = 4}

2) -5x - 8 = 2

Add 8 to both sides

 -5x - 8 + 8 = 2 + 8

            -5x  = 10

Divide both sides by (-5)

            \sf \dfrac{-5}{-5}x =\dfrac{10}{-5}

                 \sf \boxed{\bf x = -2}

3) 12r - 14 = 5(2-r)

    12r - 14 = 5*2 - 5*r

     12r - 14 = 10 - 5r

Add 14 to both sides

 12r - 14 + 14 = 10 - 5r + 14

             12r  = 24 - 5r

Add 5r to both sides

        12r + 5r = 24

               17r = 24

Divide both sides by 17

                 r = 24/17

4) 3x - 8 = -(17 + 2x)

  3x - 8 = -17 - 2x

Add 8 to both sides

3x - 8 + 8 = -17 - 2x + 8

           3x = -9 - 2x

Add 2x to both sides

      3x + 2x = -9

            5x  = -9

Divide both sides by 5

              \sf \dfrac{5}{5}x=\dfrac{-9}{5}\\\\\boxed{x = \dfrac{-9}{5}}

3 0
2 years ago
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Can someone please explain to me how to do this.
JulijaS [17]
Y = x² - 4x + 4
y = 2x - 4

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x² - 6x + 8 = 0
<span> (x - 2)(x - 4) = 0
x = 2 or x = 4

When x = 2 , y = 2(2) - 4 = 0
When x = 4, y = 2(4) - 4 = 4

Points of intersection = A(2, 0) and B(4, 4)

Find the length of AB:

</span>&#10;\text {Length of AB}=  \sqrt{(4-0)^2 + (4-2)^2} =  \sqrt{16 + 4} = \sqrt{20}  = 4.47 \text{ units}
<span>
Answer: 4.47 units

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3 years ago
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11Alexandr11 [23.1K]

Answer:

4 1/4

Step-by-step explanation:

f(x) = 2/3(6) + 1/4

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Answer:

$41.50 profit

Step-by-step explanation:

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Second, 60-18.50=41.50

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Paha777 [63]

Answer: 23

Step-by-step explanation:

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3 years ago
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