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aev [14]
3 years ago
15

Which number has the same absolute value as -21

Mathematics
2 answers:
MArishka [77]3 years ago
7 0

Answer:

it would be 21

the only difference is that one is a negative and the other is a positive. The absolute value is the distance the number is from 0 on the number line.

hope i helped :)

Inga [223]3 years ago
3 0

Answer:

21

Step-by-step explanation:

|-21| = 21

The absolute value is the distance the number is from 0 on the number line.

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Fred's frog jumped 7 times as far as Al's frog. The two fogs jumped a total of 56 inches. How far did Fred's frog jump?
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Let us assume that Al’s frog jumped X inches.
Fred’s frog jumped 7X inches.
Total distance covered by both frogs is 56 inches.
Then X+7X=56
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3 years ago
Determine mu Subscript x overbar and sigma Subscript x overbar from the given parameters of the population and sample size. mu e
Mademuasel [1]

Answer:

\bar x \sim N(\mu_{\bar x}=86, \sigma_{\bar x}=3)

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".  

Solution to the problem

Let X the random variable who represents the variable of interest. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =86,\sigma =24)  

We select a sample of size n=64. That represent the sample size.  

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:  

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})  

The mean for the sample distirbution would be given by:

\mu_{\bar x}=86

And the deviation given by:

\sigma_{\bar x} =\frac{24}{\sqrt{64}}=3

And then the distribution for the sample mean is:

\bar x \sim N(\mu_{\bar x}=86, \sigma_{\bar x}=3)

7 0
3 years ago
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