Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
-6x - 10 > 14 + 2x
<u>-2x </u> <u> -2x </u>
-8x - 10 > 14 THIS IS THE MISSING STEP
<u> +10</u> <u>+10 </u>
-8x > 24
x < -3
Answer: x < -3
Answer:
Both 
and 
are solutions to the system.
Step-by-step explanation:
In order to determine whether the two given points represent solutions to our system of equations, we must "plug" thos points into both equations and check that the equality remains valid.
Step 1: Plug into 
The solution verifies the equation.
Step 2: Plug into 
The solution verifies both equations. Therefore, is a solution to this system.
Now we must check if the second point is also valid.
Step 3: Plug into
Step 4: Plug into
The solution verifies both equations. Therefore, is another solution to this system.
Answer:
3.8×10^7= 38000000
1.9×10^6= 1900000
38000000÷1900000= 20
the population of California is 20 greater than the population of Nebraska
