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uysha [10]
3 years ago
6

A particular milliampere-seconds value, regardless of the combination of milliamperes and time, will reproduce the same radiogra

phic density. This is a statement of the
A. line-focus principleB. inverse-square lawC. reciprocity lawD. law of conservation of energy
Physics
1 answer:
finlep [7]3 years ago
3 0

Answer:

C. Reciprocity law

Explanation:

The reciprocity law is based on the assumption that the density or blackening of a photographic film is dependent merely on the exposure or quantity of radiant energy which the film absorbs and is independent of the rate at which the energy is applied.

This law pertains to the milliampere-seconds in the sense that all combinations of milliamperes and time  that amount to an equal quantity will produce the same amount of radiographic density.

The answer is:

C. Reciprocity law

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In deserts the temperatures can reach extreme values in deep of summer and winter. A steel bridge is being constructed and it is
ryzh [129]

Answer:

The length of the bridge during the hottest part of summer is L_s  = 1235.925 m

Explanation:

From the question we are told that

    The length of the steel bridge is L = 1234.567m

     The temperature for this length is T_1 = 233.15K

     The temperature at summer T_2  = + 140.0F = \frac{140 - 32}{180} *100  + 273= 333 K

     The coefficient of linear expansion is \alpha  = 11.0123*10^{-6} K^{-1}

Generally the change in length of the steel bridge is mathematically represented as

             \Delta L = \alpha L \Delta T

Substituting value

             \Delta L = 11.0123*10^{-6}  * 1234.567 (333-233.15)

              \Delta L = 1.3575 \ m

The length of the bridge in summer is mathematically evaluated as

         L_s  = L + \Delta L

Substituting values

         L_s  = 1234.567 + 1.3575

        L_s  = 1235.925 m

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3 years ago
A 15.0-kilogram mass is moving at 7.50 meters per second on a horizontal, frictionless surface. What is the
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The answer is 570 J. The kinetic energy has the formula of 1/2mV². The total work in this process W= 1/2m(V2²-V1²) = 1/2 * 15.0 * (11.5²-7.50²) = 570 J.
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4 years ago
Hallar la distancia que recorre una movil al cabo
Kryger [21]

Answer:

Distancia, S = 136 metros

Explanation:

Dados los siguientes datos;

Aceleración, a = 3 m/s²

Velocidad inicial, u = 5 m/s

Tiempo, t = 8 segundos

Para encontrar la distancia recorrida, usaríamos la segunda ecuación de movimiento;

S = ut + ½at² Sustituyendo en la fórmula, tenemos;

S = 5 × 8 + ½ × 3 × 8²

S = 40 + 1,5 × 64

S = 40 + 96

Distancia, S = 136 metros

3 0
3 years ago
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