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Dmitriy789 [7]
3 years ago
11

You have a concave mirror of focal length 20 cm. You want to obtain a real image of double the

Physics
1 answer:
ExtremeBDS [4]3 years ago
6 0

Between centre of curvature and principal focus.

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A cat is chasing a mouse across a 1.3 m tall dining table. The mouse darts to the side and the cat accidentally slides off, land
erastovalidia [21]

Answer:

1) 0.51 seconds.

2) 1.45 m/s.

Explanation:

given, height from which cat falls = 1.3 m

we know that, s = ut + \frac{1}{2}at².

here if we consider cat moment only in downward direction,

intial velocity of cat in downward direction , u = 0.

so, time, t = \sqrt{\frac{2h}{g} }.

⇒ t = \sqrt{\frac{2(1.3)}{9.81} } = 0.51 seconds.

t = 0.51 seconds.

now, consider cat moment only in forward direction

s = ut , since acceleration is zero in forward direction

⇒ u = \frac{s}{t}.

so, u = \frac{0.75}{0.51} = 1.45 m/s .

6 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS AND I NEED ALL CORRECT ANSWERS ONLY!!!
Dominik [7]

the purpose of fuses and circuit breakers is (first answer)

7 0
3 years ago
Read 2 more answers
Which is more dense, cold freshwater or warm seawater?
svp [43]
Cold freshwater<span> is </span>denser<span> than </span>warm seawater<span>, because of the salinity and temperature variations. Cold water would have less salt since the solubility of the salt is lower as compared to warm water. Hope this answers the question. Have a nice day.</span>
4 0
3 years ago
Read 2 more answers
an object is thrown into the air with an initial velocity of 12 meters per seconds from a platform that is raised 4 meters above
butalik [34]

Answer:

1.52 seconds

Explanation:

Step 1: identity the given parameters

Initial velocity (u) = 12m/s

Height above ground (h1) = 4m

Final velocity (V) = 0

Step 2: calculate the height travelled by the object from 4m height (h2).

V^2 = U^2 -2gh

0= 12^2-2(9.8*h)

2(9.8*h) = 12^2

19.6*h = 144

h = 144/19.6

h = 7.347 m

Total height above ground (ht) = 4m +7.347m = 11.347m

Step 3: calculate the time reach ground

T = √(2h/g)

T = √(2*11.347/9.8)

T= √(22.694/9.8)

T= √2.316

T= 1.52 seconds

8 0
3 years ago
The grounded conductor and the grounding conductor are one and the same conductor and perform the same function.
STALIN [3.7K]

Answer:

Grounded  used to carry the current in the normal conditions. while on the other side grounding is refer to that safety wire that is connected to the earth and currently does not transmit through it.

As grounding wire is referred to as safety wire hence it carries current only in an emergency like a short circuit.

Explanation:

A grounded conductor is referred to as one of the wire that needed in an electric circuit. it is basically a neutral conductor.  It used to carry the current in the normal conditions. while on the other side grounding is refer to that safety wire that is connected to the earth and currently does not transmit through it.

As grounding wire is referred to as safety wire hence it carries current only in an emergency like a short circuit.

5 0
3 years ago
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