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evablogger [386]
3 years ago
13

If one shines a laser with wavelength λ = 650 nm through a single slit of width a = 0.04 mm, draw the diffraction pattern you mi

ght expect on a screen 10 m behind slit. How far apart are the minima ?

Physics
1 answer:
Alex777 [14]3 years ago
8 0

Answer:

y = 162.5 mm

Explanation:

given,

wavelength of the laser, λ = 650 nm

width of the slit, a = 0.04 mm

distance, D = 10 m                      

now, distance apart the minima is equal to

  y =\dfrac{\lambda D}{d}          

  y =\dfrac{650 \times 10^{-9}\times 10}{4 \times 10^{-5}}

         y = 0.1625 m            

         y = 162.5 mm

minima is 162.5 mm apart.

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The distance from earth to mars ranges between 780,000,000 km and 380,000,000 km depending on the time of the year. The speed of
ivann1987 [24]

Answer:

The minimum time, t = 21.11 m

Explanation:

Given,

The maximum distance between the Earth and Mars, d = 780,000,000 km

The maximum distance between the Earth and Mars, d = 780,000,000 km

The speed of the light, c = 300,000 km/s

The distance and speed of the object is related using the formula,

                           v = d / t

                            t = d / v

The minimum time it takes for data transmission is when the distance between the Mars and the Earth is at minimum.

Therefore,

                            t = 380,000,000 km / 300,000 km/s

                              = 1266.67 s

                              = 21.11 minutes

Hence, the minimum time it takes for data transmitted by the Mars Surveyor to reach earth, t = 21.11 minutes

6 0
3 years ago
What is the purpose of draeing a free-body diagrams
maria [59]
In order to see what forces are acting upon an object in every direction.
3 0
3 years ago
A 57 kg person in a rollercoaster moving through the bottom of a curved track of radius 42.7 m feels a normal force of 995 N. Ho
natita [175]

Answer:

Use Fc centripetal force as positive and W the weight as negative

N = m v^2 / R + m g

v^2 = (N - m g) R / m

v^2 = (995 - 57 * 9.8) 42.7 / 57 = 327 m^2/s^2

v = 18.1 m/s

Note: N - m g is the net force producing the centripetal force

5 0
3 years ago
A point charge of -2 µC is located at the origin. A second point charge of 6 µC is at x = 1 m, y = 0.5 m. Find the x and y coord
Soloha48 [4]

Answer:

x coordinate = -1.66 m

y coordinate is = -0.825m

Explanation:

Suppose z be the distance form the first charge and z + sqrt(1^2 +.5^2) be the distance from the second So z + sqrt(1+.25) = z + 1.12

We have k*2.0x10^-6/s^2 = k*6x10^-6/(s+1.12)^2

0.0356s^2 -0.019s-0.0897=0  

s=1.876m

The angle of the line between the two charges is arctan(.5/1) = 26.6o

x coordinate = -1.876*cos(26.6) = -1.66m

y coordinate is -1.876*sin(26.6) = -0.825m

3 0
3 years ago
A plane is flying a circular path at a speed of 55.0 m/ s, with a radius of 18.3 m. The centripetal force needed to maintain thi
Nadusha1986 [10]

The plane has a centripetal acceleration <em>a</em> of

<em>a</em> = <em>v</em> ²/<em>r</em>

where <em>v</em> is the plane's tangential speed and <em>r</em> is the radius of the circle. By Newton's second law,

<em>F</em> = <em>mv</em> ²/<em>r</em>

Solve for the mass <em>m</em> :

<em>m</em> = <em>Fr</em>/<em>v</em> ² = (3000 N) (18.3 m) / (55.0 m/s)² ≈ 18.1 kg

7 0
3 years ago
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