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Lady bird [3.3K]
3 years ago
5

A cab ride costs $4 plus $1.75 per mile driven

Mathematics
2 answers:
Darina [25.2K]3 years ago
8 0
Admission= $4.00
1 Mile After Admission= $1.75

So let's say u drove 1 Mile to your house from the store:

$4.00+$1.75=$5.75
IceJOKER [234]3 years ago
4 0

y = total cost

x = miles driven

y =4 +1.75x

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3(x+4/9)-1/2(x+ 1/3)=5/6<br> PLEASE HELP
qaws [65]

Answer:

x=-2/15

Step-by-step explanation:

6 0
3 years ago
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Help me on 12 and 13 please
posledela

Answer:

12. h=3

13. h=-3

Step-by-step explanation:

12. Recall that -2^{x-h} is a horizontal shift since h is being applied within the operation to the input. This means that h will slide the function left or right. Since the function f has a point at (1,-2) and g has the same point at (4,-2) then the function has moved 3 units 1+3=4 to the right. h=3.

13. Once again, h is a horizontal shift meaning the graphs has moved left or right only. Looking at g it has a point at (-2,2) while f has the same point at (1,2). So the graph f has moved to the left 3 units. This is h=-3 since 1+-3 = -2.

5 0
3 years ago
Consider the inequality -20.2 &gt; 0y. Which of the following must be true? Check all that apply. You cannot divide by zero. The
Katarina [22]

Answer:

You can not divide by zero.

The inequality is equivalent to - 20.2 > 0 which is false.

Step-by-step explanation:

We can not divide both sides by zero, because if we divide both sides by zero, then the inequality becomes

- \frac{20.2}{0} > y

⇒ - ∞ > y, which is not possible.

Again, the given inequality is - 20.2 > 0 × y.

We have to multiply y with zero and a product of zero with any term is also zero.

Hence, the inequality becomes - 20.2 > 0.

Therefore, the inequality is equivalent to - 20.2 > 0 which is false. (Answer)

4 0
3 years ago
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What is the value of A when we rewrite 2^x-6 + 2x as A * 2^x?
Leto [7]

Algebraic expressions are expressions that use numbers and variables

The value of A is 65/64

<h3>How to determine the value of A</h3>

The expression is given as:

2^{x - 6} + 2^x

Rewrite the expression as:

2^{x - 6} + 2^x = \frac{2^x}{2^6} + 2^x

Factor out 2^x

2^{x - 6} + 2^x = 2^x(\frac{1}{2^6} + 1)

Rewrite as product

2^{x - 6} + 2^x = 2^x * (\frac{1}{2^6} + 1)

The expression to compare with is given as: A * 2^x.

So, we have:

A * 2^x  =2^x * (\frac{1}{2^6} + 1)

Divide both sides by 2^x

A =\frac{1}{2^6} + 1

Take LCM

A =\frac{1 + 2^6}{2^6}

A =\frac{65}{64}

Hence, the value of A is 65/64

Read more about expressions at:

brainly.com/question/4344214

6 0
2 years ago
Two sets of equatic expressions are shown below in various forms: Line 1: x2 + 3x + 2 (x + 1)(x + 2) (x + 1.5)2 − 0.25 Line 2: x
kherson [118]

Answer:  The correct line is

\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.

Step-by-step explanation:  We are given the following two sets of quadratic expressions in various forms:

\textup{Line 1: }x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25,\\\\\textup{Line 2 :}x^2+5x+6=(x+2)(x+3)=(x+2.5)^2+6.25.

We are to select one of the lines from above that represent three equivalent expressions.

We can see that there are three different forms of a quadratic expression in each of the lines:

First one is the simplified form, second is the factorised form and third one is the vertex form.

So, to check which line is correct, we need to calculate the factorised form and the vertex form from the simplified form.

We have

\textup{Line 1: }\\\\x^2+3x+2\\\\=x^2+2x+x+2\\\\=x(x+2)+1(x+2)\\\\=(x+1)(x+2),

and

x^2+3x+2\\\\=x^2+2\times x\times 1.5+(1.5)^2-(1.5)^2+2\\\\=(x+1.5)^2-2.25+2\\\\=(x+1.5)^2-0.25.

So,

\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.

Thus, Line 1 contains three equivalent expressions.

Now,

\textup{Line 2: }\\\\x^2+5x+6\\\\=x^2+3x+2x+6\\\\=x(x+3)+2(x+3)\\\\=(x+2)(x+3),

and

x^2+5x+6\\\\=x^2+2\times x\times 2.5+(2.5)^2-(2.5)^2+6\\\\=(x+2.5)^2-6.25+6\\\\=(x+2.5)^2-0.25\neq (x+2.5)^2+6.25.

So,

\textup{Line 2 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2+6.25.

Thus, Line 2 does not contain three equivalent expressions.

Hence, Line 1 is correct.

7 0
3 years ago
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