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maksim [4K]
3 years ago
8

Csc2theta=csctheta/2costhetaCan you help verify the identity

Mathematics
1 answer:
Yakvenalex [24]3 years ago
7 0

csc(2x) = csc(x)/(2cos(x))

1/(sin(2x)) = csc(x)/(2cos(x))

1/(2*sin(x)*cos(x)) = csc(x)/(2cos(x))

(1/sin(x))*1/(2*cos(x)) = csc(x)/(2cos(x))

csc(x)*1/(2*cos(x)) = csc(x)/(2cos(x))

csc(x)/(2*cos(x)) = csc(x)/(2cos(x))

The identity is confirmed. Notice how I only altered the left hand side (LHS) keeping the right hand side (RHS) the same each time.

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\implies {\blue {\boxed {\boxed {\purple {\sf {x\:=\:33}}}}}}

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