The distance between both lines is 2.24 units
Step-by-step explanation:
There is no straight method to find the distance between two lines. The distance can be found out by finding a point on one line and then finding the distance of that point from the other line. The y-coordinate of point is obtained by putting any value of x in equation . The x and y combined give us the point.
Given
We have to find the distance of this point from y=2x+5
The formula for finding distance of a point (x,y) from a line is:
A=2
B=-1
C=5
Putting the values in the formula
Rounding off will give: 2.24 units
The distance between both lines is 2.24 units
Keywords: Equations of lines
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Answer:
x = 3
Step-by-step explanation:
The external angle of a triangle is equal to the sum of the 2 opposite interior angles
∠ QRT is an external angle, thus
∠ QRT = ∠ RTS + ∠ RST, substitute values
45x = 25x + 57 + x
45x = 26x + 57 ( subtract 26x from both sides )
19x = 57 ( divide both sides by 19 )
x = 3
Answer:
y = (7/2)x -20
Step-by-step explanation:
The given line is in slope-intercept form, so you can read its slope from the equation.
y = mx + b . . . . . m is the slope; b is the y-intercept
y = -(2/7)x + 9 . . . . . . has slope -2/7
The perpendicular line will have a slope that is the negative reciprocal of this, so will be ...
m = -1/(-2/7) = 7/2
We can use this and the given point to write the equation in point-slope form.
y = m(x -h) +k . . . . . . line with slope m through point (h, k)
We have m = 7/2, (h, k) = (4, -6) so the equation is ...
y = (7/2)(x -4) -6
y = (7/2)x -20
Know the order of operations. However, one of the trickiest things about solving an algebra<span> equation as a beginner is knowing where to start. Luckily, there's a specific order for solving these problems: first </span>do<span> any math operations in parentheses, then </span>do<span> exponents, then multiply, then divide, then add, and finally subtract</span>
Answer:
-3.
Step-by-step explanation:
= 6(Sum+8) = 30
= 6Sum + 48 = 30
= 6Sum = -18
= Sum = -3
Hope this helps you :)
