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faust18 [17]
3 years ago
13

To save money, a local charity organization wants to target its mailing requests for donations to individuals who are most suppo

rtive of its cause. They ask a sample of 5 men and 5 women to rate the importance of their cause on a scale from 1 (not important at all) to 7 (very important). The ratings for men were M1 = 6.2. The ratings for women were M2 = 5.3. If the estimated standard error for the difference is equal to 0.25, then consider the following. (a) Find the confidence limits at an 80% CI for these two independent samples. (Round your answers to two decimal places.)
Mathematics
1 answer:
Naya [18.7K]3 years ago
4 0

Answer:

(0.55525, 1.24475)

Step-by-step explanation:

Given that to save money, a local charity organization wants to target its mailing requests for donations to individuals who are most supportive of its cause.

                     Men    women

Sample size      5        5

Mean rate        6.2     5.3

Mean diffference = 6.2-5.3=0.9

Std error for difference = 0.25 (given)

Since we have two groups and also sample sizes are very small we can use t significant value for finding out confidence interval

df = 5+5-2 =8

t critical value for 80% two tailed = 1.397

Conf interval 80%

=(0.9-1.397*0.25, 0.9+1.397*0.25)\\= (0.55525, 1.24475)

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storchak [24]

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<h3 /><h3>$34 + $8</h3><h3>= $42</h3><h3><u>Andre Paid A Total of $42</u></h3>

<h3>7.75% × $6 ÷ 100</h3><h3>= 0.465 × 2</h3><h3>= 0.93%</h3><h3><u>Andre Saved 0.93% In Total At The Sale</u></h3>

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8 0
3 years ago
Read 2 more answers
4) A random sample of students at Westcott Elementary were asked how many siblings they had. The following data was collected: 0
netineya [11]
A) 0
B) 6
C) middle number, or middle 2, averaged, so 3
D) 1
E) 4
F) 6-0 = 6
6 0
3 years ago
A fence must be built to enclose a rectangular area of 45 comma 000 ftsquared. Fencing material costs $ 3 per foot for the two s
Tatiana [17]

Answer:

150 feet by 300 feet.

Step-by-step explanation:

The fence is to enclose a rectangular area of 45,000 ft squared.

If the dimensions of the rectangle are x and y

Area of a rectangle = xy

  • xy=45000
  • x=\frac{45000}{y}

Perimeter of the Rectangle =2x+2y

Fencing material costs $ 3 per foot for the two sides facing north and south and ​$6 per foot for the other two sides.

  • Cost of Fencing, C=$(6*2x+3*2y)=$(12x+6y)

Substitute x=\frac{45000}{y} into the Cost to get C(y)

C=12x+6y

C(y)=12(\frac{45000}{y})+6y\\C(y)=\frac{540000+6y^2}{y}

The value at which the cost is least expensive is at the minimum point of C(y), when the derivative is zero.

C^{'}(y)=\dfrac{6y^2-540000}{y^2}

\dfrac{6y^2-540000}{y^2}=0\\6y^2-540000=0\\6y^2=540000\\y^2=\frac{540000}{6} =90000\\y=\sqrt{90000}=300

Recall,

x=\frac{45000}{y}=\frac{45000}{300}=150

Since x=150, y=300

The dimensions that will be least expensive to build is 150 feet by 300 feet.

6 0
3 years ago
At the movie theatre, child admission is $5.90
Alik [6]
Let the number of children be c, and the number of adults be a.
c + a = 170 (total number of tickets)
Then the cost of each is: $5.90/child, $9.60/adult:
5.9c + 9.6a = 1269.40 (total sales)
Solving as 2 simultaneous equations, we first transform the first equation:
a = 170 - c
Substitute into the 2nd equation:
5.9c + 9.6(170 - c) = 1269.40
Solving gives c = 98, and a = 170 - 98 = 72. This means that 72 adult tickets were sold that day.
5 0
3 years ago
Helppp!!!! please!!!
Kamila [148]

Answer:

<h2>           a.   1188 in.² </h2>

Step-by-step explanation:

Area of parallelogram is:  A = B•H     {H⊥B}

B = 36 in.

H = 33 in.

A = 36 in. • 33 in. = 1188 in.²

7 0
3 years ago
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