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faust18 [17]
3 years ago
13

To save money, a local charity organization wants to target its mailing requests for donations to individuals who are most suppo

rtive of its cause. They ask a sample of 5 men and 5 women to rate the importance of their cause on a scale from 1 (not important at all) to 7 (very important). The ratings for men were M1 = 6.2. The ratings for women were M2 = 5.3. If the estimated standard error for the difference is equal to 0.25, then consider the following. (a) Find the confidence limits at an 80% CI for these two independent samples. (Round your answers to two decimal places.)
Mathematics
1 answer:
Naya [18.7K]3 years ago
4 0

Answer:

(0.55525, 1.24475)

Step-by-step explanation:

Given that to save money, a local charity organization wants to target its mailing requests for donations to individuals who are most supportive of its cause.

                     Men    women

Sample size      5        5

Mean rate        6.2     5.3

Mean diffference = 6.2-5.3=0.9

Std error for difference = 0.25 (given)

Since we have two groups and also sample sizes are very small we can use t significant value for finding out confidence interval

df = 5+5-2 =8

t critical value for 80% two tailed = 1.397

Conf interval 80%

=(0.9-1.397*0.25, 0.9+1.397*0.25)\\= (0.55525, 1.24475)

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1. In which quadrant or on which axis do each of the points (-2,4) , (3,-1) ,(-1,0), (1,2) and (-3,-5) lie? Verify your answer b
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Point (-2 , 4) lies in the 2nd quadrant

Point (3 , -1) lies in the 4th quadrant

Point (-1 , 0) lies on the negative part of the x-axis

Point (1 , 2) lies in the 1st quadrant

Point (-3 , -5) lies in the 3rd quadrant

Step-by-step explanation:

Let us revise the signs of the coordinates in each quadrant

  • x and y coordinates are positive in the 1st quadrant
  • x-coordinate is negative and y-coordinate is positive in the 2nd quadrant
  • x and y coordinates are negative in the 3rd quadrant
  • x-coordinate is positive and y-coordinate is negative in the 4th quadrant
  • The general point on the positive part of x-axis is (x , 0), and on the negative part of x-axis is (-x , 0)
  • The general point on the positive part of y-axis is (0 , y), and on the negative part of y-axis is (0 , -y)

Now let us check the points

Point (-2 , 4) ⇒ red point

∵ x = -2 and y = 4

∵ x-coordinate is negative and y-coordinate is positive

∴ Point (-2 , 4) lies in the 2nd quadrant

Point (3 , -1) ⇒ blue point

∵ x = 3 and y = -1

∵ x-coordinate is positive and y-coordinate is negative

∴ Point (3 , -1) lies in the 4th quadrant

Point (-1 , 0) ⇒ green point

∵ x = -1 and y = 0

∵ x-coordinate is negative and y-coordinate is zero

∴ Point (-1 , 0) lies on the negative part of the x-axis

Point (1 , 2) ⇒ purple point

∵ x = 1 and y =2

∵ x and y coordinates are positive

∴ Point (1 , 2) lies in the 1st quadrant

Point (-3 , -5) ⇒ black point

∵ x = -3 and y = -5

∵ x and y coordinates are negative

∴ Point (-3 , -5) lies in the 3rd quadrant

<em>Look to the attached graph for more understand</em>

Learn more:

You can learn more about the four quadrant in brainly.com/question/9381523

#LearnwithBrainly

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2 years ago
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