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kolbaska11 [484]
3 years ago
5

When testing the claim that p 1p1equals=p 2p2​, a test statistic of zequals=2.04 is obtained. Find the ​p-value obtained from th

is test statistic.
Mathematics
1 answer:
AURORKA [14]3 years ago
8 0

Answer:

0.0414 with an upper tailed test

Step-by-step explanation:

Claim: P1P1 = P2P2

The above is a null hypothesis

The alternative hypothesis for a two-tailed test would be:

P1P1 \=/ P2P2

Where "\=/" represents "not equal to".

Using a z-table or z-calculator, we derive the p-value (probability value) for the z-score 2.04

With an upper tailed test, the

2 × [probability that z>2.04] = 2[0.0207] = 0.0414

This is the p-value for the test statistic.

Focus is on the alternative hypothesis.

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From 82 books to 138 books<br><br> Find the percent increase. Round to the nearest percent.
FrozenT [24]

Answer:

68%

Step-by-step explanation:

Calculate percentage change

from V1 = 82 to V2 = 138

(V2−V1)|V1|×100

=(138−82)|82|×100

=5682×100

=0.682927×100

=68.2927%change

=68.2927%increase

=68%

3 0
3 years ago
a department store sells a pair of shoes with an 87% markup if the store bought the pair of shoes for $55.25 what is the selling
Pani-rosa [81]
64 dollars. 55.25 divided by .87=63.5, round to nearest dollar and you get 64 dollars
6 0
3 years ago
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​Simplify. ​13(−32.48−14.02)​ Enter your answer, as a decimal to tenths, in the box.
Artyom0805 [142]

If you mean 1/3 the answer is -15.5

1/3(-32.48-14.02) = 1/3(-46.5) = (-15.5)

3 0
3 years ago
A researcher is studying a mouse population in a field. For the first year of her study, she notices that the mouse population d
Montano1993 [528]

Answer:

The 500 mice would be the carrying capacity of the field being studied.

Step-by-step explanation:

For the first year of study, the mouse population demonstrates exponential growth.

But by third year, the mouse population has stabilized at approximately 500 mice.

Thus, this 500 mice would be the carrying capacity of the field being studied.

Carrying capacity is defined as the measure to demonstrate the maximum population size that any given environment can sustain for an unspecified time period.

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3 years ago
12 and 1 half minus 9 and 5 12’s
PolarNik [594]
The answer to this is 3.083
6 0
3 years ago
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