Given that a polynomial function P(x) has rational coefficients.
Two roots are already given which are i and 7+8i,
Now we have to find two additional roots of P(x)=0
Given roots i and 7+8i are complex roots and we know that complex roots always occur in conjugate pairs so that means conjugate of given roots will also be the roots.
conjugate of a+bi is given by a-bi
So using that logic, conjugate of i is i
also conjugate of 7+8i is 7-8i
Hence final answer for the remaining roots are (-i) and (7-8i).
Step-by-step explanation:
A + 2 ÷ (-24) = -4
A - 1/12 = -4
A = -4 + 1/12
A = -48/12 + 1/12
A = -47/12
A ≈ -3,91
Step-by-step explanation:
1.(4,9) & (1,6)
m=y²-y¹/x²-x¹
m=6-9/1-4
m=-3/-3
m= 1
2.(5,3) & (5,-9)
m=y²-y¹/x²-x¹
m=(-9)-3/5-5
m=-12/0
3.(2,1) & (8,9)
m=y²-y¹/x²-x¹
m=9-1/8-2
m=8/6
m= 4/3
4.(14,-8) & (7,-6)
m=y²-y¹/x²-x¹
m=(-6)-(-8)/7-14
m=2/-7
m= -2/7
5.(4,-3) & (8,-3)
m=y²-y¹/x²-x¹
m=(-3)-(-3)/8-4
m=0/4
m=0
6.(-11,1) & (-2,6)
m=y²-y¹/x²-x¹
m=6-1/(-2)-(-11)
m=5/9
The correct answer is 5(p+r) because sum means add
Hope this helped :)
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Which steps would you use to solve this equation? p+7=12
We can solve this equation in one step only, and this is the step:-
Subtract 7 from both sides
p=12-7
p=5
<h3>Good luck.</h3>
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