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stellarik [79]
4 years ago
15

When does the confirmation bias occur?

Mathematics
1 answer:
zvonat [6]4 years ago
4 0

Answer:

I believe it is A

Step-by-step explanation:

Bias is considered unfair because it’s based of that one persons belief answer A best explains that

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Need help on this question writing linear equations
Mrrafil [7]

if you look at delta y over x, you'll notice it always equals 2

i.e (22-2)/10-0 = 20/10 = 2

or (14-2)/6-0 = 12/6 = 2

or even (22-8)/10-3 = 14/7 = 2

This means that m (slope) is 2.

Now as for b. b is the y intercept and that value occurs when x = 0. On the table, when x = 0 y = 2 so b = 2.

y = mx + b becomes

y = 2x + 2

6 0
3 years ago
Algebra 1 Check Answer Please
BigorU [14]
The answer is the third one.

The way I think through these problems is that where you multiply (-7x), you use addition, and where you use addition (-4), you multiply.

The answers added together will equal the second number, -7, and multiplied will give you the third, -4.

What you had chosen as the answer was close. But 7.53+-0.53 equals positive 7, not negative. However they do round to -4 when multiplied.

The correct answer, -7.53 and 0.53, do equal -7 when added together and equal -4 when multiplied.
5 0
3 years ago
Will give brainlist to the best answer if possible!! 10 points please help
Black_prince [1.1K]

Answer:

B

Step-by-step explanation:

y= -x+18 and y= 3/4x+4

use slope intercept form: y=mx+b

m = slope

b = y-intercept

4 0
2 years ago
Let D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36} Determine which of the following statements are true and which are false. a)
morpeh [17]

Answer:

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is even then x≤0 is false statement.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

Step-by-step explanation:

Consider the provided information.

D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36}

Part (A) \forall x\in D if x is odd then x> 0

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (B) \forall x\in D if x is less than 0 then x is even.

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (C) \forall x\in D if x is even then x≤0

Here we can see that 16, 26, 32, 36 are even number and also greater than 0. Thus the statement is false.

\forall x\in D if x is even then x≤0 is false statement.

Part (D) \forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4.

There is only one number whose ones digit is 2. i.e. 32 also the tens digit of the number 32 is 3. Which makes the above statement true.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

Part (E) \forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2.

Numbers having ones digit 6 are: 16, 26 and 36

Here, the tens digits are 1, 2 and 3 which is contradict to our statement. Hence the provided statement is false.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

8 0
3 years ago
IREADY suck so can I help
dem82 [27]

Answer: the plus sign

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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