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svetoff [14.1K]
3 years ago
14

Triangles Unit Test part 1 A length of rope is stretched between the top edge of a building and a stake in the ground. The head

of the stake is at ground level. The rope also touches a tree that is growing halfway between the stake and the building. If the tree is 16 feet tall, how tall is the building?

Mathematics
1 answer:
musickatia [10]3 years ago
5 0

Answer:

The building is 32 feet tall.

Step-by-step explanation:

Consider the figure drawn below representing the given scenario.

AB represents the height of building, BC is the distance between the stake and building, C represents the stake at ground level, and DE represents the height of the tree growing halfway between building and stake.

Since the tree is growing halfway between B and C, therefore, the point E divides the line segment BC into 2 equal parts.

Therefore, BE = EC or E is the midpoint of BC.

Also, from the figure, it is clear that both tree and building are vertical to the ground. So, DE || AB.

Now, from converse of mid-segment theorem, if a line passes through the midpoint of one side of a triangle and also parallel to the third side, then the line also passes through the midpoint of the second side and half the length of the third side (parallel side)

So,

DE=\frac{1}{2}\times AB\\\\16=\frac{AB}{2}\\\\AB=16\times 2=32\ ft

Therefore, the building is 32 feet tall.

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Answer:

<h3>1. t=10</h3><h3>2. t=4</h3><h3>3. t=40</h3>

Step-by-step explanation:

Isolate the term of t from one side of the equation.

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First, you have to divide by 4 from both sides.

4t/4=40/4

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Divide the numbers from left to right.

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<h3><u>t=10</u></h3>

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First, subtract by 70 from both sides.

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Divide by -1 from both sides.

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<u />

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I hope this helps! Let me know if you have any questions.

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2 years ago
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