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Natalka [10]
3 years ago
8

Find the number of real solutions of each equation using the discriminant.

Mathematics
1 answer:
lianna [129]3 years ago
8 0

Answer: 1: x^2 + 25 = 0 x=5

2: x^2 - 11x + 28 = 0 x=7 i think

3: x^2 + 8x + 16 = 0 x=-4

Step-by-step explanation:

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Which of the following is a composite number that is divisible by both 3 and 5?A.116B.135C.1025D.1546
BlackZzzverrR [31]
The answer is B. 135.
6 0
3 years ago
Help please and make sure the answer is right! Please :(
likoan [24]

You see how these 2 angles marked are both inside the 2 parallel lines?

And they are on opposite side of the transversal, the line crossing the 2 parallel lines?

These 2 angles are alternate interior angles and they are equal, I think you can do the last part by yourself.

8 0
3 years ago
X/5-2=x/2+3 solve for x
Makovka662 [10]
Solve for x:x/5 - 2 = x/2 + 3
Put each term in x/5 - 2 over the common denominator 5: x/5 - 2 = x/5 - (10)/5:x/5 - (10)/5 = x/2 + 3
x/5 - (10)/5 = (x - 10)/5:(x - 10)/5 = x/2 + 3
Put each term in x/2 + 3 over the common denominator 2: x/2 + 3 = x/2 + 6/2:(x - 10)/5 = x/2 + 6/2
x/2 + 6/2 = (x + 6)/2:(x - 10)/5 = (x + 6)/2
Multiply both sides by 10:(10 (x - 10))/5 = (10 (x + 6))/2
10/5 = (5×2)/5 = 2:2 (x - 10) = (10 (x + 6))/2
10/2 = (2×5)/2 = 5:2 (x - 10) = 5 (x + 6)
Expand out terms of the left hand side:2 x - 20 = 5 (x + 6)
Expand out terms of the right hand side:2 x - 20 = 5 x + 30
Subtract 5 x from both sides:(2 x - 5 x) - 20 = (5 x - 5 x) + 30
2 x - 5 x = -3 x:-3 x - 20 = (5 x - 5 x) + 30
5 x - 5 x = 0:-3 x - 20 = 30
Add 20 to both sides:(20 - 20) - 3 x = 20 + 30
20 - 20 = 0:-3 x = 30 + 20
30 + 20 = 50:-3 x = 50
Divide both sides of -3 x = 50 by -3:(-3 x)/(-3) = 50/(-3)
(-3)/(-3) = 1:x = 50/(-3)
Multiply numerator and denominator of 50/(-3) by -1:Answer:  x = (-50)/3
7 0
3 years ago
I need help :( this problem is very confusing
Sladkaya [172]

Answer:

Emily ,  don't put your whole name in the questions :DDDD, it's at the top of the page, anyway,     Eloper   .. :DDD

Step-by-step explanation:

It's arithmetic  b/c  you're just adding  1

arithmetic

1

1

are the answers ,  the last one is b/c that's the common difference.

6 0
3 years ago
Read 2 more answers
What is the area, in square inches, of the isosceles trapezoid below?
zimovet [89]

Answer:

104.8 in^2

Step-by-step explanation:

There are 2 ways to solve this problem.

The 1st way:

Let's make 2 triangles and 1 rectangle:

Rectangle Length = 8.3

Rectangle Width = 8

So, the left out length will be 17.9 - 8.3

=> 9.6

Since, 9.6 cm is for 2 parts.

=> 9.6 / 2

=> 4.8

So, Height of the Triangle = 8

      Base of the triangle = 4.8

Area of a rectangle

=> 8.3 x 8

=> 66.4

Area of the triangle

=> 1/2 x 8 x 4.8

=> 4 x 4.8

=> 19.2

There are 2 triangles:

=> 19.2 x 2

=> 38.4

=> 66.4 + 38.4

=> 104.8

The area of the trapezoid = 104.8 in^2.

The 2nd way is:

Area of a trapezoid

=> Smaller Base + Larger Base / 2 x Height

=> 8.3 + 17.9 / 2 x 8

=> 26.2 / 2 x 8

=> 13.1 x 8

=> 104.8

The area of the trapezoid is 104.8 in^2

6 0
3 years ago
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