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PolarNik [594]
3 years ago
9

Surface area.. please answer

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
6 0
160, I think. SA=2(lw+lh+wh).
frosja888 [35]3 years ago
5 0

\boxed{ \mathfrak{\huge \: \underline{ \underline{A nswer} }: }}

Given terms :

\hookrightarrow \: length = 8 \: in

\hookrightarrow \: width = 2 \: in

\hookrightarrow \: height = 12 \: in

we know,

\large\boxed{ \mathrm{surface \:  \: area \: (a) = 2(lw + wh + lh)}}

\hookrightarrow  \mathrm{\: a =  2 \times \bigg [(8 \times 2) + (2 \times 12) + (8 \times 12) \biggr]}

\hookrightarrow a = 2 \times \biggr[16 + 24 + 96 \biggr]

\hookrightarrow \: a =  \bigg [\:  2 \times 136\bigg ]

\hookrightarrow \large \boxed{ \mathrm{a = 272 \:  \: in {}^{3} }}

____________________________________

\mathrm{✌TeeNForeveR✌}

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Answer:

<u>The true statement is D</u>

Step-by-step explanation:

The rest of the question is the attached figure and the statement options.

  • A. Over the interval [–4, –2], the local minimum is 0.
  • B. Over the interval [–2, –1], the local minimum is 25.
  • C. Over the interval [–1, 4], the local minimum is 0.
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============================================================

According to the graph, we will check the options:

A. Over the interval [–4, –2], the local minimum is 0.  (<u>Wrong</u>)

Because the minimum is -12

B. Over the interval [–2, –1], the local minimum is 25.   (<u>Wrong</u>)

Because the minimum is 18

C. Over the interval [–1, 4], the local minimum is 0.  (<u>Wrong</u>)

Because the minimum is at x = 4 less than zero

D. Over the interval [4, 7], the local minimum is -7.    (<u>True</u>)

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Step-by-step explanation:

45 is the answer and hope this helps!

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