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Ludmilka [50]
4 years ago
8

C) Si x representa un número, escribe una

Mathematics
1 answer:
lawyer [7]4 years ago
3 0

YAnswer:

Step-by-step explanation:

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20% of Ms. Martin's class did not complete their homework. If there are 30 students in her class, how many did not complete home
padilas [110]

Answer:

Step-by-step explanation:

20% of 30 is 6

Words: 6 Students in Ms. Martin's class did not do their homework.

hope this helps :)

7 0
2 years ago
a tray is fill with several 500g bags of apples. the tray holds 8 kg in total. 5 bags of apples are sold .how many is left on th
kobusy [5.1K]
8kg=8000g

8000/500=16
16-2=14
5 0
3 years ago
A company makes 140 bags.
Igoryamba

Answer: 41/75 or 54.67%

Step-by-step explanation:

Buttons --- yes,  zips --- yes = 45  (compute as 150 - 37 - 45 - 23)

Buttons --- yes,  zips --- no  = 37

Buttons --- no, zips --- yes = 45

Buttons --- no, zips --- no = 23

Therefore, 82 out of 150 bags have buttons so probability = 82/150 = 41/75

7 0
2 years ago
An individual who has automobile insurance from a certain company is randomly selected. Let y be the number of moving violations
Hoochie [10]

Answer:

a) E(Y)= \sum_{i=1}^n Y_i P(Y_i)

And replacing we got:    

E(Y) = 0*0.45 +1*0.2 +2*0.3 +3*0.05= 0.95

b) E(80Y^2) =80[ 0^2*0.45 +1^2*0.2 +2^2*0.3 +3^2*0.05]= 148

Step-by-step explanation:

Previous concepts

In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".  

The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).  

And the standard deviation of a random variable X is just the square root of the variance.  

Solution to the problem

Part a

We have the following distribution function:

Y        0         1         2       3

P(Y)  0.45    0.2    0.3   0.05

And we can calculate the expected value with the following formula:

E(Y)= \sum_{i=1}^n Y_i P(Y_i)

And replacing we got:    

E(Y) = 0*0.45 +1*0.2 +2*0.3 +3*0.05= 0.95

Part b

For this case the new expected value would be given by:

E(80Y^2)= \sum_{i=1}^n 80Y^2_i P(Y_i)

And replacing we got

E(80Y^2) =80[ 0^2*0.45 +1^2*0.2 +2^2*0.3 +3^2*0.05]= 148

5 0
3 years ago
I NEED HELP, Please
Lerok [7]

Answer:

C)

Step-by-step explanation:

g has to be less than 7.2

The only number that fulfills this demand is C) which is 5

3 0
4 years ago
Read 2 more answers
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