Check the picture below.
well, the volume of the craft prism will simply be length * width * height, and we know that is 7140.
![\textit{volume of a rectangular prism}\\\\ V=Lwh ~~ \begin{cases} L=length\\ w=width\\ h=height\\[-0.5em] \hrulefill\\ L=17\\ h=28\\ V=7140 \end{cases}\implies \begin{array}{llll} 7140=(17)w(28)\implies \cfrac{7140}{(17)(28)}=w \\\\\\ 15=w \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20rectangular%20prism%7D%5C%5C%5C%5C%20V%3DLwh%20~~%20%5Cbegin%7Bcases%7D%20L%3Dlength%5C%5C%20w%3Dwidth%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20L%3D17%5C%5C%20h%3D28%5C%5C%20V%3D7140%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%207140%3D%2817%29w%2828%29%5Cimplies%20%5Ccfrac%7B7140%7D%7B%2817%29%2828%29%7D%3Dw%20%5C%5C%5C%5C%5C%5C%2015%3Dw%20%5Cend%7Barray%7D)
we know the area of the top is just w * 17, and the circle is just 2/5 of that, well that's just

Answer:
Step-by-step explanation:
Hi...
I dont speak spanish
Answer:

Step-by-step explanation:
Let A1 be the area of one square and A2 be the area of second square
So,
A1 = s^2
where s is side of square

So side of one square is 
To calculate the length of fence we need to find the perimeter of the square
So,
P1 = 4 * s

For second square:

The perimeter will be:

So the total fence will be: P1+P2

Answer:
Step-by-step explanation:
1. x=20/4
x=5
2. x=2*7
x=14
3. x=2/3
4. x=7*2
x=14