Answer:
For 32 bits Instruction Format:
OPCODE DR SR1 SR2 Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE
= 12 + 3 = 15
Total number of bits for instruction format = 32
Maximum No. of Unused bits = 32 – 15 = 17 bits
OPCODE DR SR1 SR2 Unused bits
3 bits 4 bits 4 bits 4 bits 17 bits
This statement would be TRUE
Answer:
A,B,D
A. Allows you to be sure the problem and solution are understood
B. Presents the solution in a manner that is easy to share
C. Is a starting point for all other activities
Answer:
count_p = 0
count_n = 0
total = 0
while True:
number = int(input("Enter an integer, the input ends if it is 0: "))
if number == 0:
break
else:
total += number
if number > 0:
count_p += 1
elif number < 0:
count_n += 1
print("The number of positives is: " + str(count_p))
print("The number of negatives is: " + str(count_n))
print("The total is: " + str(total))
print("The average is: " + str(total / (count_p + count_n)))
Explanation:
Initialize the variables, count_p represens the number of positives, count_n represents the number of negatives, and total represents the total of the numbers
Create a while loop iterates until the user enters 0. If the number is not 0, then add it to the total. If the number is greater than 0, increase count_p by 1. If the number is smaller than 0, increase count_n by 1.
When the loop is done, print the count_p, count_n, total, and average
Dynamic Host Configuration Protocol, also known as DHCP.
