Give four characteristics of hard disk

In order to be compliant with the NIST publications, policies must include key security control requirements. One of these key r

lesya692 [45]

Answer:

True

Explanation:

In order to be compliant with the NIST publications, policies must include key security control requirements. One of these key requirements includes certification and accreditation, which is a process that occurs after the system is documented, controls tested, and risk assessment completed. It is required before going live with a major system. Once a system is certified and accredited, responsibility shifts to the owner to operate the system is a true statement.

8 0

3 years ago

Which principle or element of layout design is highlighted in this event poster?

Oduvanchick [21]

The principle or element of layout design is highlighted in an event poster in option i: The headline.

<h3>What are the elements of page layout?</h3>

The poster is known to be one that often uses a kind of hierarchy and centered text alignment as its element.

Note that it is one whose Lines of use is said to be made up of different kinds of type styles, sizes and others.

The simple elements of an advertising poster is made up of:

1. The headline.

2. The sub-head.

3. The body copy.

4. The caption.

The elements of page layout are visual hierarchy, visual flow, and others. Hence, the principle or element of layout design is highlighted in an event poster in option i: The headline.

Learn more about layout design from

brainly.com/question/2501083

#SPJ1

6 0

2 years ago

The various online technology tools that enable people to communicate easily via the Internet to share information and resources

seropon [69]

Answer:

Social media is the correct answer for the above question.

Explanation:

Social media is the media that is used to communicate with the other person with the help of an internet connection. There is so much software that gives this type of facility. for example whats up and twitter.
The above question asked about that technology which is used to connect the people to communicate and the technology is social media which gives the features to connect and communicate all over the world with the help of the internet. Hence "Social media" is the correct answer.

8 0

3 years ago

Determine and prove whether an argument in English is valid or invalid. About Prove whether each argument is valid or invalid. F

yawa3891 [41]

Answer:

Each understudy on the respect roll got an A.

No understudy who got a confinement got an A.

No understudy who got a confinement is on the respect roll.

No understudy who got an A missed class.

No understudy who got a confinement got an A.

No understudy who got a confinement missed class

Explanation:

M(x): x missed class

An (x): x got an A.

D(x): x got a confinement.

¬∃x (A(x) ∧ M(x))

¬∃x (D(x) ∧ A(x))

∴ ¬∃x (D(x) ∧ M(x))

The conflict isn't considerable. Consider a class that includes a lone understudy named Frank. If M(Frank) = D(Frank) = T and A(Frank) = F, by then the hypotheses are overall evident and the end is counterfeit. Toward the day's end, Frank got a control, missed class, and didn't get an A.

Each understudy who missed class got a confinement.

Penelope is an understudy in the class.

Penelope got a confinement.

Penelope missed class.

M(x): x missed class

S(x): x is an understudy in the class.

D(x): x got a confinement.

Each understudy who missed class got a confinement.

Penelope is an understudy in the class.

Penelope didn't miss class.

Penelope didn't get imprisonment.

M(x): x missed class

S(x): x is an understudy in the class.

D(x): x got imprisonment.

Each understudy who missed class or got imprisonment didn't get an A.

Penelope is an understudy in the class.

Penelope got an A.

Penelope didn't get repression.

M(x): x missed class

S(x): x is an understudy in the class.

D(x): x got a repression.

An (ax): x got an A.

H(x): x is on the regard roll

An (x): x got an A.

D(x): x got a repression.

∀x (H(x) → A(x)) a

¬∃x (D(x) ∧ A(x))

∴ ¬∃x (D(x) ∧ H(x))

Real.

1. ∀x (H(x) → A(x)) Hypothesis

2. c is a self-self-assured element Element definition

3. H(c) → A(c) Universal dispatch, 1, 2

4. ¬∃x (D(x) ∧ A(x)) Hypothesis

5. ∀x ¬(D(x) ∧ A(x)) De Morgan's law, 4

6. ¬(D(c) ∧ A(c)) Universal dispatch, 2, 5

7. ¬D(c) ∨ ¬A(c) De Morgan's law, 6

8. ¬A(c) ∨ ¬D(c) Commutative law, 7

9. ¬H(c) ∨ A(c) Conditional character, 3

10. A(c) ∨ ¬H(c) Commutative law, 9

11. ¬D(c) ∨ ¬H(c) Resolution, 8, 10

12. ¬(D(c) ∧ H(c)) De Morgan's law, 11

13. ∀x ¬(D(x) ∧ H(x)) Universal hypothesis, 2, 12

14. ¬∃x (D(x) ∧ H(x)) De Morgan's law, 13

4 0

3 years ago

The birthday paradox says that the probability that two people in a room will have the same birthday is more than half, provided

poizon [28]

Answer:

The Java code is given below with appropriate comments for explanation

Explanation:

// java code to contradict birth day paradox

import java.util.Random;

public class BirthDayParadox

{

public static void main(String[] args)

{

Random randNum = new Random();

int people = 5;

int[] birth_Day = new int[365+1];

// setting up birthsdays

for (int i = 0; i < birth_Day.length; i++)

birth_Day[i] = i + 1;

int iteration;

// varying number n

while (people <= 100)

{

System.out.println("Number of people: " + people);

// creating new birth day array

int[] newbirth_Day = new int[people];

int count = 0;

iteration = 100000;

while(iteration != 0)

{

count = 0;

for (int i = 0; i < newbirth_Day.length; i++)

{

// generating random birth day

int day = randNum.nextInt(365);

newbirth_Day[i] = birth_Day[day];

}

// check for same birthdays

for (int i = 0; i < newbirth_Day.length; i++)

{

int bday = newbirth_Day[i];

for (int j = i+1; j < newbirth_Day.length; j++)

{

if (bday == newbirth_Day[j])

{

count++;

break;

}

iteration = iteration - 1;

}

System.out.println("Probability: " + count + "/" + 100000);

System.out.println();

people += 5;

}

4 0

3 years ago

Give four characteristics of hard disk​

Give four characteristics of hard disk