Answer:
48 mph
Step-by-step explanation:
First we need to find the distance from Elkhart to Chicago. Toledo to Elkhart is 136 miles and Toledo to Chicago 244 miles.
So the distance from Elkhart to Chicago can be calculated, since Chicago is farther from Toledo than Elkhart, as: distance(Toledo to Chicago) - distance(Toledo to Elkhart). These distances are given in the problem, so the distance from Elkhat to Chicago is: 244 miles - 136 miles = 108 miles.
This problem basically wants to know the slowest you can be yet still ariving on time. If you are the minimum speed, you will arrive in Chicago exactly at 10:30 A.M. So you have 2 hours and 15 minutes(10:30 A.M - 8.15A.M.) to drive 108 miles.
15 minutes is a fourth of a hour, so you have 2.25hours to go through 108 miles.
The minimum speed you must maintain is 108mph/2.25h = 48mph.
Answer:
= 3 3/4 m^2
or 15/4 m^2
Step-by-step explanation:
The base is the triangle.
A =1/2 bh
A = 1/2 (3 1/3 * 9/4)
Change 3 1/3 to an improper fraction (3*3+1)/3 = 10/3
A = 1/2 * 10/3 *9/4
Re arranging
= 1/2* 9/3 * 10/4
= 1/2 (3) 5/2
=15/4
Now writing as a mixed number
= 3 3/4 m^2
Answer:
(10/3, 2/3)
Step-by-step explanation:
You may find it easier to write these two equations x+y=4 2x-y=6 in a column:
x+y=4
2x-y=6
Adding these together will eliminate y:
3x = 10. Then x = 10/3.
Substituting 10/3 for x in the first equation results in:
10/3 + y = 4
Clear fractions by multiplying all three terms by 3:
10 + 3y = 12
Then 3y = 2, and y = 2/3.
The solution is (10/3, 2/3)
Answer:
8! 8x8=64 lol
Step-by-step explanation:
Hope this helps, And have a good day!