Based on your problem, you only have one given. So, you can't make an equation for this because there are not limits to the equation. The only thing that you know is that the three numbers are consecutive even integers. My way of solution for this is trial-and-error. However, it's really quite easy.
For example: 42 + 46 = 88. I have to increase the numbers more to reach 136. Suppose: 82 + 86 = 168. That exceeded 136. So, it must be between 46 and 82. Suppose again: 66 + 70 = 136. Therefore, the sequence of the consecutive even integers are 66, 68, and 70.
Answer:
Go through the explanation you should be able to solve them
Step-by-step explanation:
How do you know a difference of two square;
Let's consider the example below;
x^2 - 9 = ( x+ 3)( x-3); this is a difference of two square because 9 is a perfect square.
Let's consider another example,
2x^2 - 18
If we divide through by 2 we have:
2x^2/2 -18 /2 = x^2 - 9 ; which is a perfect square as shown above
Let's take another example;
x^6 - 64
The above expression is the same as;
(x^3)^2 -( 8)^2= (x^3 + 8) (x^3 -8); this is a difference of 2 square.
Let's take another example
a^5 - y^6 ; a^5 - (y ^3)^2
We cannot simplify a^5 as we did for y^6; hence the expression is not a perfect square
Lastly let's consider
a^4 - b^4 we can simplify it as (a^2)^2 - (b^2)^2 ; which is a perfect square because it evaluates to
(a^2 + b^2) ( a^2 - b^2)
Answer:
3·(x - 14) + 1 = - 4·x + 5
3·x - 42 + 1 = - 4·x + 5
3·x - 41 = - 4·x + 5
7·x - 41 = 5
7·x = 46
x = 46/7
Answer:
Test statistic is [(n - 1) *S^2 ]/ σ ^2 = [(22 - 1) *(3.9)^2 ]/ (3.4) ^2
with 21 degrees of freedom
Yes this data fits at the 10% level of significance, so I would not reject that statistic of 3.9 mmHg as a wrong standard deviation
Step-by-step explanation:
use the expression I attached in the image to find
[(n - 1) *S^2 ]/ σ ^2
where S = the standard deviation calculated from the sample of n trials.
sigma is the population standard deviation.
[(22 - 1) *(3.9)^2 ]/ (3.4) ^2 = 21 * 15.21 / 11.56 = 27.6306
all we have to do now is to make sure this number is in the 90 % confidence
interval. remember this has 21 degrees of freedom, look at the chi-squared chart.
11.5913 < 27.6306 < 32.67905
where 11.5913 is the lower bound of the chart
and 32.67905 is the upper bound
3.26d+9.75d-2.65
=13.01d−2.65