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3 years ago

Moosonee: -1.5°C

Mathematics

2 answers:

Ne4ueva [31]3 years ago

6 0

Answer:

Moscow is the warmer then othe

Kazeer [188]3 years ago

4 0

Answer:

Moscow

Step-by-step explanation:

In negatives the greater number is less. So -1 is the greatest, and thus, Moscow is the answer.

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3 years ago

757.923 expanded form

tamaranim1 [39]

The expanded form is adding all the digits so the answer is
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3 years ago

I NEED HELP!!!!!!!!!

ANEK [815]

Answer:

the number --4

Step-by-step explanation:

-7--4=-3

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3 years ago

Lorraine writes the equation shown. x squared + y minus 15 = 0 She wants to describe the equation using the term relation and th

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

Step 2: Find Arc Length

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

4 0

3 years ago