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Ghella [55]
3 years ago
7

ASAP

Mathematics
1 answer:
DerKrebs [107]3 years ago
6 0
25%

explanation:

3.5-2.8/2.8
0.7/2.8
0.25
25%
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Hank is opening a special investment CD account that offers 0.45% interest compounded monthly. The account requires a minimal in
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3 years ago
The weight of an object on a particular scale is 145.2 lbs. The measured weight may vary from the actual weight by at most 0.3 l
joja [24]

1. Know what you're looking for:

The range is the difference between the lowest and highest values.

Your weight is 145.2 and can vary from the actual weight by maximum 0.3 lbs less or maximum 0.3 lbs more.


2. Calculate your lowest and highest values :


Lowest : 145.2 - 0.3 = 144.9 lbs

Highest : 145.2 + 0.3 = 145.5 lbs


3. Calculate the range of actual weights of the object :


145.5 - 144.9 = 0.6 lbs


--> The answer is: <u>The range of actual weights of the object is 0.6 lbs.</u>


There you go! I really hope this helped, if there's anything just let me know! :)

4 0
3 years ago
How many ways are there to select a 5-card hand from a regular deck such that the hand contains at least one card from each suit
Snezhnost [94]

Answer:

There are 685464 ways of selecting the 5-card hand

Step-by-step explanation:

Since the hand has 5 cards and there should be at least 1 card for each suit, then there should be 3 suits that appear once in the hand, and one suit that apperas twice.

In order to create a possible hand, first we select the suit that will appear twice. There are 4 possibilities for this. For that suit, we select the 2 cards that appear with the respective suit. Since there are 13 cards for each suit, then we have {13 \choose 2} = 78 possibilities. Then we pick one card of all remaining 3 suits. We have 13 ways to pick a card in each case.

This gives us a total of 4*78*13³ = 685464 possibilities to select the hand.

6 0
3 years ago
There are 28 students in a class. 13 of the students are boys. Two students from the class are chosen at random. a) If the first
Luba_88 [7]

Answer:

Step-by-step explanation:

3 0
2 years ago
Which expression is equivalent to x y Superscript two-ninths?
crimeas [40]

Option D: x\sqrt[9]{y^2} is the expression equivalent to xy^{\frac{2}{9}}

Explanation:

Option A: \sqrt{xy^9}

The expression can be written as ({xy^9})^{\frac{1}{2}

Applying exponent rule, we get,

x^{\frac{1}{2}} y^{\frac{9}{2}}

Thus, the expression \sqrt{xy^9} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option A is not the correct answer.

Option B: \sqrt[9]{xy^2}

The expression can be written as ({xy^2})^{\frac{1}{9}

Applying exponent rule, we get,

x^{\frac{1}{9}} y^{\frac{2}{9}}

Thus, the expression \sqrt[9]{xy^2} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option B is not the correct answer.

Option C: x\sqrt{y^9}

The expression can be written as x(y^9)^{\frac{1}{2} }

Applying exponent rule, we get,

x y^{\frac{9}{2}}

Thus, the expression x\sqrt{y^9} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option C is not the correct answer.

Option D: x\sqrt[9]{y^{2} }

The expression can be written as x(y^2)^{\frac{1}{9} }

Applying exponent rule, we get,

xy^{\frac{2}{9}}

Thus, the expression xy^{\frac{2}{9}} is equivalent to the expression xy^{\frac{2}{9}}

Hence, Option D is the correct answer.

4 0
3 years ago
Read 2 more answers
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