Answer:
(A) A web page will not display in a browser unless it passes syntax validation testing.
(C)A web page must pass syntax validation testing before it is used.
Explanation:
A website is a collection of related web pages. A web page is an electronically arranged content page, designed and developed using web development application and language tool and hosted on a web server.
Web page or application development follows a series of well defined stages called software development life cycle (SDLC). The web application must go through these processes from birth to the end-of-life of the application.
The validation testing in SDLC, consisting of unit, acceptance and loading testing, which checks for syntax error or bugs on the written codes, because bugs could slow the loading of the page or even the display and browser compatibility of elements in the code.
Answer:
A. 50 percent
Explanation:
The correct option is - A. 50 percent
Another preventive measure you can take is to maintain the relative humidity at around 50 percent. Be careful not to increase the humidity too far—to the point where moisture starts to condense on the equipment.
Answer:
Storage management
Explanation:
The programs that do this are known as Storage management programs. They are incredibly useful since they allow you to see which files are taking up the most amount of space as well as the importance that each file has on the system. Many of these programs have a different visual representation of the files such as pie charts or system blocks showing the percentage of space it is taking up. Everything in these programs is made to help the end-user visualize and analyze their data thoroughly.
Hi pupil here's your answer ::
➡➡➡➡➡➡➡➡➡➡➡➡➡
Column A Column B
1》CD = Optical Storage Devices
2》Hard Disk = Magnetic Storage Device
3》Flash Memory = Solid State Storage
⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅
Hope this helps. . . . . . .
Answer:
#include<iostream>
using namespace std;
int main (){
int n1, n2;
cout<<"Enter 1st number";
cin>>n1;
cout<<"Enter 2nd number";
cin>>n2;
if(n1<n2){
cout<<"The 1st number is the smallest"<<endl<<" is= "<<n1;
}
else{
cout<<"The 2nd number is the smallest"<<endl<<" is= "<<n2;
}
}
return 0;
