Answer:
(7, 0) and (-5, 0)
Step-by-step explanation:
<u>Vertex form</u>
(where (h, k) is the vertex)
Given:

Given:



Therefore:

The x-intercepts are when y = 0






Therefore, the x-intercepts are (7, 0) and (-5, 0)
Answer:
(х-4)(х-6)
Step-by-step explanation:
х¹= 4
х²=6
easy
Answer:
f(x) = (-1/2)(x^2 + 8x - 15)
Step-by-step explanation:
This function has two roots: -3 and 5. Most likely it is a quadratic (all of which have two roots).
Then f(x) = a(x + 3)(x - 5)
The graph goes through (1. 8): Therefore, y = 8 when x = 1:
f(1) = a(1 + 3)(1 - 5) = 8, or
a(4)(-4) = 8, or
-16a = 8, which leads to a = -1/2.
Thus the quadratic in question is f(x) = (-1/2)(x + 3)(x - 5), or
f(x) = (-1/2)(x^2 + 8x - 15)
Answer:
3, in both a), b)
Step-by-step explanation:
a) The slope of the line tangent to the curve that passes through the point (2,-10) is equal to the derivative of p at x=2.
Using differentiation rules (power rule and sum rule), the derivative of p(x) for any x is
. In particular, the value we are looking for is
.
If you would like to compute the equation of the tangent line, we can use the point-slope equation to get 
b) The instantaneus rate of change is also equal to the derivative of P at the point x=2, that is, P'(2). This is equal to
.