109 with a remainder of 6
Please give brainliest

- Given - <u>a </u><u>cone </u><u>with </u><u>base </u><u>radius </u><u>9</u><u>m</u><u>m</u><u> </u><u>and </u><u>height </u><u>1</u><u>3</u><u> </u><u>mm</u>
- To calculate - <u>volume </u><u>of </u><u>the </u><u>cone</u>
We know that ,

<u>su</u><u>b</u><u>stituting </u><u>the </u><u>values</u><u> </u><u>in </u><u>the </u><u>formula</u><u> </u><u>,</u>

hope helpful ~
Answer = 0
n can have possible values from (-12) to 12
-12 <= n < 12
(-12) + (-11)+(-10)......+10+11+12=0
Answer:
area = 138 m²
Step-by-step explanation:
radius of large circle = 12 m
radius of small circle = 10 m
large circle area = πr² = (3.14)(12²) = 452.16 m²
small circle area = πr² = (3.14)(10²) =314 m²
452.16 - 314 = 138.16 m²