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krok68 [10]
2 years ago
13

Which equation represents a line that passes through (–2, 4) and has a slope of StartFraction 2 Over 5 EndFraction.? y – 4 = (x

+ 2) y + 4 =(x – 2) y + 2 = (x – 4) y – 2 =(x +4)
Mathematics
2 answers:
JulijaS [17]2 years ago
8 0

For this case we have that by definition, the point-slope equation of a line is given by:

(y-y_ {0}) = m (x-x_ {0})

Where:

(x_ {0}, y_ {0}): It is a point through which the line passes

m: It is the slope of the line

According to the data we have to:

(x_ {0}, y_ {0}): (-2,4)\\m = \frac {2} {5}

Substituting:

y-4 = \frac {2} {5} (x - (- 2))\\y-4 = \frac {2} {5} (x + 2)

Finally, the equation of the line is:

y-4 = \frac {2} {5} (x + 2)

ANswer:

y-4 = \frac {2} {5} (x + 2)

levacccp [35]2 years ago
7 0

Answer:

The answer is A

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Answer:

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Step-by-step explanation:

7*2=14, 14-1=13

vise versa

f(13)=2(7)-1

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The inverse is effectively the opposite of the original relation. It undoes what the original relation does. So we'll swap the x and y values for each given point in the form (x,y). Something like (8,-1) becomes (-1,8). The other points follow the same pattern as well.

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The sum of three consecutive odd integers is 17 less than four times the smallest integer. Find the integers.
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23, 25, 27

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6 0
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What number would you add to the equation below to complete the square?x2 + 4x = 0?
julia-pushkina [17]
------------------------------------------------------------------
Equation
------------------------------------------------------------------
x² + 4x = 0

------------------------------------------------------------------
Add a constant
------------------------------------------------------------------
x² + 4x + (4/2)² - (4/2)²  = 0   ← Add 2² to form perfect square

------------------------------------------------------------------
Evaluate bracket
------------------------------------------------------------------
x² + 4x + 2² - 2² = 0

------------------------------------------------------------------
Form the perfect square
------------------------------------------------------------------
(x + 2)² = 4 

------------------------------------------------------------------
Square root both sides
------------------------------------------------------------------
(x+2) = \pm √4

------------------------------------------------------------------
Evaluate the square root
------------------------------------------------------------------
(x+2) = \pm 2

------------------------------------------------------------------
Solve x 
------------------------------------------------------------------
x = 2 - 2 or x = -2 - 2

x = 0 or -4

------------------------------------------------------------------
Answer: The constant to add is 4 and the value of x = 0 or -4
------------------------------------------------------------------



7 0
3 years ago
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