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julia-pushkina [17]
3 years ago
8

Which description best compared the graph of the two functions below?

Mathematics
1 answer:
Alenkinab [10]3 years ago
5 0

Answer:

The description that best compares the graph of the two function is:

         The line for function A is steeper.

Step-by-step explanation:

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Someone please help!!<3
Nataliya [291]

Answer:

the answer is c

Step-by-step explanation:

the answer is c

4 0
3 years ago
Bro what does this mean
dimulka [17.4K]

Answer:

A

Step-by-step explanation:

hope this helps

8 0
3 years ago
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A couple is required by their lender to have a down payment of 20% of the purchase price of the home they want to buy. If the co
Stella [2.4K]

Down payment is 20% of the price of the home. Since the couple saved $35,000, and assuming they will pay the whole money as down payment, the highest priced home they can get is a price whose 20% is $35,000.

We can setup an equation in x (being the price of home) to get the price of the most expensive home they can buy.

<em>Which number (x) , multiplied by 20%, is equal to $35,000?</em>

<em>x(0.2)=35,000\\x=\frac{35,000}{0.2} \\x=175,000</em>

So, the most expensive house they can buy is worth $175,000.


ANSWER: $175,000

7 0
3 years ago
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Find the volume of a cone
lianna [129]

Answer:

96π or 301.59 in³

Step-by-step explanation:

V(cone) = 1/3πr²h

= 1/3·π·6²·8

= 96π or 301.59

6 0
3 years ago
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What are the domain restrictions of the expression g2−7g+10g3−6g2+8g ? Select each correct answer.
Sauron [17]

Answer with Step-by-step explanation:

We are given that an expression

f(g)=\frac{g^2-7g+10}{g^3-6g^2+8g}

We have to find domain restriction of the given function.

f(g)=\frac{(g-5)(g-2)}{g(g-4)(g-2)}

Domain restriction means : It is that value of x when substitute in function then  function will  not defined.

It means it is that values which makes denominator zero.

From given function we can see that

When substitute g=0 then it makes denominator zero.

Hence, the function is not defined at g=0

Substitute g=4

Then, it makes denominator zero.

Hence, function is not defined  at g=4

Substitute g=2

Then,it  makes denominator zero.

Hence, function is not defined  at g=2

Therefore, the function is defined for all values of g except g=0, g=2 and g=4

5 0
3 years ago
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