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andrew-mc [135]
3 years ago
7

Solve similar triangles can someone please answer

Mathematics
1 answer:
hram777 [196]3 years ago
4 0

Answer:

With this sort of geometric problem, all you need to do is look and identify, to narrow down your answer. Particularly, you should pick up on any trends. I'm hoping you noticed that using the other two points, you can see that they are dividing by three from the red shape to get the blue shape sides. And you should also notice that the shape is flipped, so if you picture it in the same position as the other one to match up the sides!

To find n, simply do 6 ÷ 3

This equals 2!

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A right triangle has side lengths 7, 24, and 25 as shown below.
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Answer: Tan B = 0.2917 (16.26 degrees)

Sin B = 0.2800 (16.26 degrees)

Cos B = 0.9600 (16.26 degrees)

Step-by-step explanation: Please refer to the picture attached for details.

The right angled triangle LNB has been drawn with the sides labeled as 7, 24 and 25 as indicated. With angle B as the reference angle, we can now identify each side as follows;

Side 7 (opposite, facing the reference angle)

Side 24 (adjacent, between the reference angle and the right angle)

Side 25 (hypotenuse, facing the right angle).

Hence, using the trigonometric ratios,

Tan B = opposite/adjacent

Tan B = 7/24

Tan B = 0.2917 (16.26 degrees)

Sin B = opposite/hypotenuse

Sin B = 7/25

Sin B = 0.2800 (16.26 degrees)

Cos B = adjacent/hypotenuse

Cos B = 24/25

Cos B = 0.9600 (16.26 degrees)

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