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kupik [55]
4 years ago
6

Write the expression as a single natural logarithm.3In3+3Inc

Mathematics
2 answers:
faltersainse [42]4 years ago
8 0

Answer:

\ln 27c^3

Step-by-step explanation:

= 3\ln 3 + 3\ln c

= \ln 3^3 + \ln c^3

= \ln 3^3c^3

= \ln 27c^3

k0ka [10]4 years ago
3 0

Answer:

ln(27c^3)

Step-by-step explanation:

Given: 3ln(3)+3ln(c)

If there is a coefficient in front of a log or ln, that means it becomes an exponent.

ln(3^3)+ln(c^3)

Simplify the exponent.

ln(27)+ln(c^3)

When there is addition between two logarithms or natural logarithms, it means they multiply together.

ln(27c^3)

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A circle has its center at the center of a square with 26-inch sides. Using 3.14 for pi, find the area of the square not covered
AlladinOne [14]
For squrae
area=side²
perimiter=4(side)

for circle
area=pir²
circumference=2pir

side=diameter, diameter/2=radius=side/2


find area not covered
that is areasquare-areacircle
areasquare=26²=676 sqauare inches
areaciecle, diameter=side, 26/2=13, area=pi13²=169*3.14=530.66 square inches

areanotcovered=676-530.66=145.34 square inches not coverd


ratio of perimiter to circumferece
perimiter=4*26=104
circumference=2pir=2pi13=26pi=26*3.14=81.64
circumference to perimiter is 81.64/104=0.785

7 0
3 years ago
Read 2 more answers
Solve the inequality :<br> x-7 ≤ 3x + 1
Nina [5.8K]

Answer:

See below.

Step-by-step explanation:

x-7≤3x+1

 +7     +7

x≤3x+8

-3x -3x

-2x≤8

/-2   /-2

x≥-4

The inequality symbol reverses when divided/multiplied by a negative term.

-hope it helps

6 0
2 years ago
Read 2 more answers
X= 2 please solve before 5 pm
MariettaO [177]

Answer:

6. y=20

7. y=3

8. y=3

Step-by-step explanation:

7 0
3 years ago
A vertical right circular cylindrical tank has height h=8 feet high and diameter d=6 feet. It is full of kerosene weighing 50 po
Mariana [72]

Answer:

The work done to  pump all of the kerosene from the tank to an outlet is W=45238.9\: J  

Step-by-step explanation:

The work is defined by:

W=\int dFdx (1)    

The force here will be the product between the volume and the kerosene weighing, so we have :

dF=\pi R^{2}dy*50

This force will be in-lbs.

Where R is the radius (3 feet)                    

Then using (1), we have:

W=\int \pi R^{2}dy*50(8-y)  

Here 8-y is a distance at some point of the tank. Now, to get the work done from the base to the top of the tank we will need to take integral from 0 to 8 feet.

W=\int_{0}^{8} \pi 3^{2}dy*50(8-y)

W=450\pi \int_{0}^{8}dy(8-y)

W=450\pi(\int_{0}^{8} 8dy-\int_{0}^{8} ydy)

W=450\pi(8y|_{0}^{8} -\frac{y^{2}}{2}|_{0}^{8})  

W=450\pi(8*8 -\frac{8^{2}}{2})

W=450\pi(64 -\frac{64}{2})

Therefore, the work done to  pump all of the kerosene from the tank to an outlet is W=45238.9\: J  

I hope it helps you!  

6 0
3 years ago
The ratio of 600m to 3km in simplest form
never [62]
3 km = 3000m
600m:3000m divide by 10
60:300 divide by 10
6:30 divide by 3
2:10 divide 2
*1:5* (simplest form)
6 0
4 years ago
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