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3 years ago

Question 6

Mathematics

1 answer:

Tamiku [17]3 years ago

8 0

Answer:

Step-by-step explanation

shes pulling RANDOM names. key word random, hope this helped

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4r^3-3r^2-4r+3 <br> four terms <br> use grouping

matrenka [14]

It’s (4r-3)(r+1)(r-1)

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3 years ago

Think of your favorite spot to get food from. You are going there to get your first meal after quarantine and the meal cost $35.

sveta [45]

Answer:

You will be paying $41.30 in total.

Step-by-step explanation:

The cost of the meal is $35 and you want to leave 18% tip on the meal.

We want to find the total amount that will be paid.

First, we have to find 18% of $35 and then, add it to the original bill ($35).

18% of 35 is:

18/100 * 35 = $6.30

The tip is $6.30, therefore, the total amount paid will be:

$35 + $6.30 = $41.30

You will be paying $41.30 in total.

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3 years ago

Answer my questions and i will mark you as brainliest i promise trust me

Kazeer [188]

Answer:

1.042g/cm^3

Step-by-step explanation:

4 0

3 years ago

Suppose p(a) = 0.40 and p(a 

sveticcg [70]

Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that

$P(A\cup B)+P(A\cap B)=P(A)+P(B)$

For parts (a) and (b), you're given everything you need to determine $P(B)$ .

For part (c), if $A$ and $B$ are mutually exclusive, then $P(A\cap B)=0$ , so $P(A\cup B)=P(A)+P(B)$ . If the given probability is $P(A\cup B)=0.55$ , then you can find $P(B)=0.15$ . But if this given probability is for the intersection, finding $P(B)$ is impossible.

For part (d), if $A$ and $B$ are independent, then $P(A\cap B)=P(A)\cdot P(B)$ .

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3 years ago

A robot that makes _/6 of a boat per day will make 5 boats in 6 days

MatroZZZ [7]

For what I understand, if a robot was to make 5/6 of a boat per day, in 6 days it will have made 5 boats. The answer is 5

4 0

2 years ago