The answer is: 10 x¹³ y¹⁰ .
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1x^8 * 2y^(10) * 5x^5 =
1* 2* 5 * x^8 * x^5 * y^(10) =
10 * x^(8+5) * y^(10) =
10 * x^(13) * y^(10) = 10 x^(13) y^10 ; write as:
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10 x¹³ y¹<span>⁰ .
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Answer:
A) Area as function of H ,
F'(a) = 2 +H
B) Area of triangle with height 6ft = 30 ft²
Step-by-step explanation:
Given as for a triangle ,
Let the height of triangle = H ft
And base = 4 ft + H ft
Now area of triangle = 
× height × base
F (a) = × H × ( 4ft + H ft)
Or, F (a) = × ( 4H + H² )
Now, here Area is function of height ,
So , F'(a) = (4 + 2H)
Hence Area as function of H ,
F'(a) = 2 +H
Now For height = 6 ft
Area of triangle = × height × base
= × H × ( 4ft + H ft)
= × ( 4H + H² )
= × ( 24 + 36 )
= × ( 60 )
= 30 ft²
Hence Area of triangle with height 6ft = 30 ft² Answer
Answer: Attributes.
Step-by-step explanation:
An attribute is characterized as a person, position, or thing's quality or characteristic. Individuals in real life and fictional characters have different characteristics. Someone could be called attractive, charming, funny, or intelligent, for instance. Well, in math, an attribute is a characteristic of a math object - it's what this object has. An attribute of the book is the number of errors in a chapter of the book.
Well, first of all, the first statement (ABC = ADC) looks like it just says
that the two halves of the little square ... each side of the diagonal ...
are congruent. That's no big deal, and it's no help in answering the
question.
The effect of the dilation is that all the DIMENSIONS of the square
are doubled ... each side of the square becomes twice as long.
Then, when you multiply (length x width) to get the area, you'd have
Area = (2 x original length) x (2 x original width)
and that's
the same as (2 x 2) x (original length x original width)
= (4) x (original area) .
Here's an easy, useful factoid to memorize:
-- Dilate a line (1 dimension) by 'x' times . . . multiply the length by x¹
-- Dilate a shape (2 dimensions) by 'x' . . . multiply area by x²
-- Dilate a solid (3 dimensions) by 'x' . . . multiply volume by x³
And that's all the dimensions we have in our world.
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Oh, BTW . . .
-- Dilate a point (0 dimensions) by 'x' . . . multiply it by x⁰ (1)
