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Furkat [3]
3 years ago
13

A car is driving down a highway at a speed of 65 miles per hour. To the nearest second, how long wili it take the car to drive 1

00 yards? ( 1 mile = 5280 feet, 1 yard = 3 feet)
Physics
1 answer:
Setler [38]3 years ago
4 0

Answer:

3.1468 sec

Explanation:

We have given the speed of the car is 65 miles/hour

The distance traveled by the car = 100 yards

As it is given that 1 yard = 3 feet

So 100 yard =100×3=300 feet

As in question it is given that 1 mile =5280 feet

So 300 feet =\frac{300}{5280}=0.0568miles

Now time taken =\frac{distance}{speed}=\frac{0.0568}{65}=8.7412\times 10^{-4}hour=3.1468sec

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Which sentence best explains the law of conservation of mass as applied to
drek231 [11]

Answer:

A. The amount of mass changes only slightly during a chemical

reaction.

3 0
2 years ago
A car accelerates from rest at 1.0 m/s2 for 20.0 second along a straight road. It then moves at a constant speed for half an hou
Whitepunk [10]

Total distance = 36500 m

The average velocity = 19.73 m/s

<h3>Further explanation</h3>

Given

vo=initial velocity=0(from rest)

a=acceleration= 1 m/s²

t₁ = 20 s

t₂ = 0.5 hr = 1800 s

t₃= 30 s

Required

Total distance

Solution

State 1 : acceleration

\tt d=vo.t+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 1\times 20^2\rightarrow vo=0\\\\d=200~m

\tt vt=vo+at\\\\vt=at\rightarrow vo=0\\\\vt=1\times 20\\\\vt=20~m/s

State 2 : constant speed

\tt d=v\times t\\\\d=20\times 1800\\\\d=36000~m

State 3 : deceleration

\tt vt=vo+at\rightarrow vt=0(stop)\\\\vo=-at\\\\20=-a.30~s\\\\a=-\dfrac{2}{3}m/s^2(negative=deceleration)

\tt d=vot+\dfrac{1}{2}at^2\\\\d=20.30-\dfrac{1}{2}.\dfrac{2}{3}.30^2\\\\d=300~m

Total distance : state 1+ state 2+state 3

\tt 200 + 36000 + 300=36500~m

the average velocity = total distance : total time

\tt avg~velocity=\dfrac{36500}{20~s+1800~s+30~s}=19.73~m/s

4 0
2 years ago
Example 2.1
tatiyna

Answer:

5 min 20 km --------

Explanation:

5 min 20 km --------

8 0
2 years ago
Which mixtures could be separated using evaporation? Check all that apply. fat in milk salt in ocean water mud in pond water but
salantis [7]
I would go with salt in ocean water as when you heat it and the water begins to evaporate it will leave the salt behind


Also water in mud as the water would evaporate and leave the mud residue behind


GOOD LUCK
BRAINLIEST IF HELPED
5 0
3 years ago
Read 2 more answers
A bowling ball of mass 5 kg rolls down a slick ramp 20 meters long at a 30 degree angle to the horizontal. What is the work done
Elena-2011 [213]

Answer:

The work done by gravity during the roll is 490.6 J

Explanation:

The work (W) is:

W = F*d

<em>Where</em>:

F: is the force

d: is the displacement = 20 m

The force is equal to the weight (W) in the x component:

F = W_{x} = mgsin(\theta)

<em>Where:</em>

m: is the mass of the bowling ball = 5 kg

g: is the gravity = 9.81 m/s²    

θ: is the degree angle to the horizontal = 30°        

F = mgsin(\theta) = 5 kg*9.81 m/s^{2}*sin(30) = 24.53 N    

Now, we can find the work:

W = F*d = 24.53 N*20 m = 490.6 J      

Therefore, the work done by gravity during the roll is 490.6 J.

I hope it helps you!

6 0
3 years ago
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