Answer:
As You know kinetic Energy is equal (mv^2)/2
You can increase it by increasing the mass(keeping the velocity)
Or You can add velocity
Explanation:
The electric potential energy of the pair of charges when the second charge is at point b is 7.3 x 10⁻⁸ J.
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Electric potential energy</h3>
When work is done on a positive test charge to move it from one location to another, potential energy increases and electric potential increases.
The electric potential energy between the charges when the second charge is at point b is calculated as follows;
ΔU = -w
Ui - Uf = w
Uf = Ui - w
where;
Uf is the final potential energy
Ui is the initial potential energy
w is the work done by the force
Uf = 5.4 x 10⁻⁸ J - (-1.9 x 10⁻⁸J)
Uf = 5.4 x 10⁻⁸ J + 1.9 x 10⁻⁸ J
Uf = 7.3 x 10⁻⁸ J
Thus, the electric potential energy of the pair of charges when the second charge is at point b is 7.3 x 10⁻⁸ J.
Learn more about electric potential energy here: brainly.com/question/14306881
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I don’t know what the answer is to the question but if I don’t answer the question I will be mad at the
Answer:
Diferencia de energía de las dos fuentes = 800 watts
Explanation:
Cantidad de energía recibida en el mar = 1000
Cantidad de energía solar recibida en el mar = 200
Diferencia de energía de las dos fuentes = 1000 -200 = 800 watts
